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Ainat [17]
4 years ago
5

How to do the problem

Mathematics
1 answer:
ruslelena [56]4 years ago
5 0

Answer:

1.) x = 14.96ft

2.) The shorter leg is 6 meters

Step-by-step explanation:

1.) a^2 + b^2 = c^2

  • a and b = legs of the triangle
  • c = hypotenuse the longest side

15ft^2 + x^2 = (2x +1)^2

  • 225 + x^2 = (2x^2 + 1^2)
  • 225 = 2x^2 + 1 - x^2
  • 225 = x^2 + 1
  • 225 - 1 = x^2 +1 - 1
  • √224 = √x^2
  • x = 14.9662...

2.) Longer leg a = x+2,  shorter leg b = x, Hyp. c= 2x-2

Equation:

  • (x+2)^2 + x^2 = (2x-2)^2

Solve:

  • (x+2)(x+2) + x^2 = (2x-2)(2x-2)
  • x^2 + 4x + 4 + x^2 = 4x^2 - 8x +4
  • 2x^2 + 4x + 4 = 4x^2 - 8x +4
  • 2x^2 + 4x + 4 - 4x^2 +8x - 4 = 4x^2 - 4x^2 - 8x + 8x + 4 - 4
  • -2x^2 + 12x = 0
  • 2x (-x + 6) = 0

Answers:

  • 2x = 0
  • -x + 6 = 0
  • <u>x=0 -or- x=6</u>

<u>Since x cannot equal 0 due to the known length of the triangle needs to be more than 0 the answer for x equals 0.</u>

<u>B=6</u>

Check:

  • A = x + 2: A= 6 +2 = 8
  • B= 6
  • C = 2x -2: C= 2(6) -2 = 10

8^2 + 6^2 = 10^2

  • 64 + 36 = 100
  • 100= 100
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Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
kompoz [17]

a.

f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}

is a proper joint density function if, over its support, f is non-negative and the integral of f is 1. The first condition is easily met as long as C\ge0. To meet the second condition, we require

\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}

b. Find the marginal joint density of X and Y by integrating the joint density with respect to z:

f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz

\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}

Then

\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy

\approx\boxed{0.12886}

c. This probability can be found by simply integrating the joint density:

\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz

\approx\boxed{0.012262}

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3 years ago
At the grocery store, sliced turkey deli meat is on sale for $11 for 2 pounds. a. What is the cost per pound of sliced turkey de
alexgriva [62]

Answer:

- $5.5 per pound

- y = 5.5x

Step-by-step explanation:

Given

$11 for 2 pounds

Solving (a): Cost per pound

This is calculated by dividing $11 by 2 pounds

Cost\ per\ pound = \frac{\$11}{2\ lb}

Cost\ per\ pound = \$5.5/\ lb

Hence, the cost per pound is $5.5 per pound

Solving (b): Represent as an equation.

If 1 pound costs $5.5 (as shown in (a))

Then

x pounds costs $5.5 * x

Cost = 5.5 * x

Cost = 5.5x

This cost is represented with y

y = 5.5x

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3 years ago
True or false?
abruzzese [7]
FALSE.

The effect of adding +3 to the argument of a function f(x) is to shift the original f(x) horizoantally 3 units to the left.
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Dayson is covering a package in the shape of a rectangular prism with wrapping paper. The package is 50 centimeters by 20 centim
goblinko [34]
<span>Dayson has 1 m2 of wrapping paper, which is 10000 cm2:
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 1 m^2 = (100 cm)^2 
 </span>1 m^2 = 10000 cm^2
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 A = 2*(50*20) + </span>2*(50*18) + 2*(18*20)
 A = <span> <span>4520 cm^2
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3 0
3 years ago
15 POINTSSSS‼️‼️
Olenka [21]

Answer:

If the company produce and sell 'x' no. of thing-a-ma-bob , then

C(x) = $ (8809 + 2.05x)

R(x) = $ 4.92x

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Step-by-step explanation:

If the company produces and sells "x" no. of thing-a-ma-bob, then,

the cost function is given by,

C(x) = $ (8809 + 2.05x) ------------------------(1)

The revenue function is given by,

R(x) = $ 4.92x -------------------------------------(2)

If C(x) = R(x), then,

4.92x = 8809 + 2.05x

⇒ 2.87x = 8809

⇒ x = \frac {8809}{2.87}

⇒ x \simeq 3069.34

So, to make a profit the company must produce and sell at least 3070 thing-a-ma-bobs.

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4 years ago
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