$\left(\frac{(x^4y^{-2})^4}{(2x^2)^2\cdot2x^0y^3}\right)^2=\\
\left(\frac{x^{16}y^{-8}}{4x^4\cdot2y^3}\right)^2=\\
\left(\frac{x^{16}y^{-8}}{8x^4y^3}\right)^2=\\
\left(\frac{x^{12}y^{-11}}{8}\right)^2=\\
\frac{x^{24}y^{-22}}{64}$

3 0

3 years ago

Of 340 male and 270 female employees at the home office of Gibraltar Insurance Company, 170 of the men and 180 of the women are

sineoko [7]

Answer:

The correct answer is 0.486.

Step-by-step explanation:

Total number of employees at the home office of Gibraltar Insurance Company is 270 + 340 = 610

Number of employees on flex time are 350, out of which 170 are men and 180 are women.

We need to find the probability that out of the given employees, a randomly chosen one is on flex time and is a man.

Favorable outcomes are 170 and total outcome is 350.

Thus the probability is given by $\frac{170}{350}$ = 0.4857≈ 0.486

5 0

3 years ago