Step 1: Find f'(x):
f'(x) = -6x^2 + 6x
Step 2: Evaluate f'(2) to find the slope of the tangent line at x=2:
f'(2) = -6(2)^2 + 6(2) = -24 + 12 = -12
Step 3: Find f(2), so you have a point on y=f(x):
f(2) = -2·(2)^3 + 3·(2)^2 = -16 + 12 = -4
So, you have the point (2,-4) and the slope of -12.
Step 4: Find the equation of your tangent line:
Using point-slope form you'd have: y + 4 = -12 (x - 2)
That is the equation of the tangent line.
If your teacher is picky and wants slope-intercept, solve that for y to get:
y = -12 x + 20
Answer:
The simplification for the expression is given as =( 7 + 2(a-3))/(a-3)
Step-by-step explanation:
To simplify the expression we will first convert the words to values in numbers and alphabets.
StartFraction 5 Over a minus 3 EndFraction minus 4 divided by 2 + StartFraction 1 Over a minus 3 EndFraction
= 5/(a-3) -4/2 + 2/(a-3)
Having done that, let's move on and simplify the expression.
5/(a-3) -4/2 + 2/(a-3)
= 5/(a-3) -2+ 2/(a-3)
= 5/(a-3) + 2/(a-3) -2
= 7/(a-3) -2
=( 7 + 2(a-3))/(a-3)
Answer:
15 units
Step-by-step explanation:
Calculate the distance d using the distance formula
d = 
with (x₁, y₁ ) = (0, - 2) and (x₂, y₂ ) = (9, 10)
d = 
= 
= 
= 
= 15
Answer:
d) 303 8/9
Step-by-step explanation:
4th term = ar^3 and 5th = ar^4 where a = first term and r = common ratio.
So ar^4 / ar^3
= r = 45/-15 = -3.
Working back,:
The first term a = ar^3/ r^3
= -15 / (-3)^3
= -15/-27
= 5/9
Sum of n terms = a * (r^n - 1)/(r-1)
= 5/9 * ((-3)^7 - 1 ) / (-3 -1)
= 303 8/9
Your answer is number 2 it is 38.2 because 26 out of 68 is a percentage of 38.24
