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prisoha [69]
3 years ago
13

The blueprint for landscaping a yard has a scale of 1/2" to 1 foot. If the bloeprint is a rectangle 18inches by 22 inches, what

are the dimensions of the yard
Mathematics
1 answer:
Rudiy273 years ago
8 0

Answer:

36x44 feet are the dimensions of the yard.

Step-by-step explanation:

Given that the blueprint for landscaping a yard has a scale of 1/2" to 1 foot.

i.e. scaling factor is 1/2 for one foot.

If real dimension is 1 foot, it is shown as 1/2 inch in blue print.

Using this we can find the real dimensions if given blue print dimensions.

The blueprint is a rectangle 18inches by 22 inches,

Hence real length of rectangle = 18(2) feet = 36 feet

Width of rectangle = 22(2) = 44 feet

i.e. the yard has dimensions as 36x44 feet.

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During halftime of a basketball ​game, a sling shot launches​ T-shirts at the crowd. A​ T-shirt is launched from a height of 4 f
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Answer:

(a) The time the T-shirt takes to maximum height is 2 seconds

(b) The maximum height is 68 ft

(c) The range of the function that models the height of the T-shirt over time given above is 4 + 64\cdot t - 16 \cdot  t^{2}

Step-by-step explanation:

Here, we note that the general equation representing the height of the T-shirt as a function of time is

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

Where:

h = Height reached by T-shirt

t = Time of flight

u = Initial velocity = 64 ft/s

g = Acceleration due to gravity (negative because upward against gravity) = 32 ft/s²

h₁ = Initial height of T-shirt = 4 ft

(a) The maximum height can be found from the time to maximum height given as

v = u - gt

Where:

u = Initial velocity = 64 ft/s

v = Final upward velocity at maximum height = 0 m/s

g = 32 ft/s²

Therefore,

0 = 64 - 32·t

32·t = 64 and

t = 64/32 = 2 seconds

(b) Therefore, maximum height is then

h = 4 + 64\times 2 - \frac{1}{2} \times 32  \times  2^{2}

∴ h = 68 ft

The T-shirt is then caught 41 ft above the court on its way down

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h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

With u = 64 ft/s

g = 32 ft/s² and

h₁ = 4 ft

The equation becomes

h =4 + 64\cdot t - \frac{1}{2} \times 32  \cdot  t^{2} = 4 + 64\cdot t - 16 \cdot  t^{2}.

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