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beks73 [17]
3 years ago
9

A bus makes 28 stops every 2 hours how many stops does t make in 3 hours? 4 hours?

Mathematics
2 answers:
Ivenika [448]3 years ago
8 0
3hours =42
4 hours =56
maw [93]3 years ago
6 0
28/2 = 14 stops every hour

3 hours = 42 stops
4 hours = 56 stops
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The sum of 36 and 3c​
VMariaS [17]

Answer:

Step-by-step explanation:

just add 36 and 3

5 0
3 years ago
How many solutions does the system have​
Delicious77 [7]

Answer:

There are infinate solutions.

Step-by-step explanation:

Plug (3x-8) in for y

5(3x-8)=15x-40

Simplify

15x-40=15x-40

4 0
3 years ago
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(1) What is the equation, in point-slope form, for a line that goes through (8, −4) and has a slope of negative 5/6 (all fractio
Andreyy89
Formula for point-slope: y - y1 = m(x-x1)
Plug in the values (1): y + 4 =  -\frac{5}{6} (x - 8)  {Choice B}
Plug in the values (2): y + 6 =  \frac{1}{3}(x+ 2)  {Choice C}
_______________________

[For (3) and (4) we need to solve for slope]

(3)
First, solve for slope.
Formula for slope: \frac{y2-y1}{x2-x1}
Plug in values: \frac{-1-5}{-4-7} = - \frac{6}{11}
Slope: - \frac{6}{11}
Second, we must plug into point-slope form. 
Formula for point-slope: y - y1 = m(x-x1)
Plug in the values: y + 1 = - \frac{6}{11}(x + 4)   {Choice C}


(4)
First, solve for slope.
Formula for slope: \frac{y2-y1}{x2-x1}
Plug in values: \frac{6-(-8)}{-4-7} = - \frac{14}{11}
Slope: - \frac{14}{11}
Second, we must plug into point-slope form. 
Formula for point-slope: y - y1 = m(x-x1)
Plug in the values: y - 6 = - \frac{14}{11}(x + 4)   {Choice D}

8 0
3 years ago
Read 2 more answers
The polynomial equation x^4 + x^3 + x^2 + x + 1 = 0 has zero positive real roots. Please select the best answer from the choices
const2013 [10]

There are zero positive real roots for the given polynomial equation x^4 + x^3 + x^2 + x + 1 = 0. This is explained by Descarte's rule of signs. So, the best choice is T (true).

<h3>What is Descarte's rule of signs?</h3>
  • Descarte's rule of signs tells about the number of positive real roots and negative real roots.
  • The number of changes in signs of the coefficients of the terms of the given polynomial f(x) gives the positive real zeros of the polynomial.
  • The number of changes in signs of the coefficients of the terms of the given polynomial when f(-x) gives the negative real zeros of the polynomial.

<h3>Calculation:</h3>

The given polynomial equation is x^4 + x^3 + x^2 + x + 1 = 0

On applying Descarte's rule of signs,

f(x)=x^4 + x^3 + x^2 + x + 1

Since there are no changes in the signs of the coefficients of any of the terms in the above polynomial, the polynomial has no positive real roots.

f(-x)=(-x)^4+(-x)^3+(-x)^2+(-x)+1\\      = x^4-x^3+x^2-x+1

Since there are four changes in the signs of the coefficients of the terms of the given polynomial when f(-x), the polynomial has 4 negative real roots.

Therefore, the given polynomial equation has zero positive real roots. So, the correct choice is T(true).

Learn more about Descarte's rule of signs here:

brainly.com/question/11590228

#SPJ1

5 0
2 years ago
HELPPP IM LOSTTTTT PLZPZLZPPZLZ
Radda [10]

Answer:

1/4

Step-by-step explanation:

rise/run = 2/8

take 2/8 and simplify

2/8 divided by 2

you get 1/4

7 0
3 years ago
Read 2 more answers
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