Answer:
1.5871
Step-by-step explanation:
According to the Question,
- we have, 7 log(15/16)+6log(8/3)+5log(2/3)+log(32/25)
The Solution, With Basic Properties of Log.
7*log15-7*log16+6*log8-6*log3+5*log2-5*log3+log32-log25
7*1.176-7*1.204+6*0.903-6*0.477+5*0.3010-5*0.477+1.505-1.3979
on Solving, We get
1.5871
Answer:
See below
Step-by-step explanation:

Answer:
1) x=3, y=-3
Step-by-step explanation:
10x + 7y = 9 —— (1)
-4x -7y = 9 —— (2)
(1) + (2)
6x = 18
x = 18/6
x = 3
put x=3 in (1)
10(3) + 7y = 9
30 + 7y = 9
7y = 9 - 30
7y = -21
y = -21/7
y = -3
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Answer: 7/25-1/25i
Step-by-step explanation: