3 years ago

One_Third of 1/2 cake=___________________ //plz help guys

Mathematics

2 answers:

alisha [4.7K]3 years ago

7 0

1/6 if you cut one whole in half and divide it by three its /6

Andreyy893 years ago

6 0

The answer is 1/6 because 1 /2 × 1/3 =1/6

You might be interested in

11/ 42 Marks

amm1812

Answer:

(a)x=128 degrees

(b) $\angle APD\neq 116^\circ$

Step-by-step explanation:

$\angle ABD+\angle CBD =180^\circ$ (Linear Postulate)\\\angle ABD+116^\circ =180^\circ\\\angle ABD=180^\circ-116^\circ\\\angle ABD=64^\circ$

(a) Now:

$\angle AOD=2 \times \angle ABD$ (Angle at the centre is twice the angle at the circumference)\\x=2 \times 64^\circ\\x=128^\circ$

(b)

$\angle APD=2 \times \angle ABD$ (Inscribed Angle Theorem)\\\angle APD=2 \times 64^\circ\\ \angle APD=128^\circ$

$\angle APD\neq 116^\circ$

7 0

2 years ago

In the number 668 the 6 in the hundreds place is _ the value of the 6 in the tens place

mihalych1998 [28]

6 in the hundreds place = 600
6 in the tens place =60

4 0

2 years ago

Subtracting integers -4 - (-5)

malfutka [58]

Answer:

the answer is 1

Step-by-step explanation:

the answer is 1

7 0

3 years ago

What do you notice about proportional relationships and linear<br> relationships

Contact [7]

Answer:

there are different

Step-by-step explanation:

8 0

2 years ago

Which polynomial function has a leading coefficient of 1 and roots 2i and 3i with multiplicity 1? f(x) = (x – 2i)(x – 3i) f(x) =

kykrilka [37]

Answer:

$P(x)=(x-2i)(x-3i)$

Step-by-step explanation:

Build a Polynomial Knowing its Roots

If we know a polynomial has roots x1, x2, ..., xn, then it can be expressed as:

$P(x)=a(x-x1)(x-x2)...(x-xn)$

Where a is the leading coefficient.

Note the roots appear with their signs changed in the polynomial.

If the polynomial has a leading coefficient of 1 and roots 2i and 3i with multiplicity 1, then:

$P(x)=1(x-2i)(x-3i)$

$\mathbf{P(x)=(x-2i)(x-3i)}$

8 0

2 years ago

Read 2 more answers