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dybincka [34]
3 years ago
7

A sequence has its first term equal to 4, and each term of the sequence is obtained by adding 2 to the previous term. If f(n) re

presents the nth term of the sequence, which of the following recursive functions best defines this sequence?
f(1) = 2 and f(n) = f(n − 1) + 4; n > 1

f(1) = 4 and f(n) = f(n − 1) + 2n; n > 1

f(1) = 2 and f(n) = f(n − 1) + 4n; n > 1

f(1) = 4 and f(n) = f(n − 1) + 2; n > 1
Mathematics
1 answer:
ra1l [238]3 years ago
5 0
The answer is the fourth option - <span>f(1) = 4 and f(n) = f(n − 1) + 2; n > 1
</span>
The first term is 4, So, f(1) = 4
The difference between two consecutive integer = 2, so, n = (n-1) + 2
It would be Option D) f(1) = 4 and f(n) = f(n − 1) + 2; n > 1

Hope this helps!
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<h3>What is an equation?</h3>

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