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dybincka [34]
4 years ago
7

A sequence has its first term equal to 4, and each term of the sequence is obtained by adding 2 to the previous term. If f(n) re

presents the nth term of the sequence, which of the following recursive functions best defines this sequence?
f(1) = 2 and f(n) = f(n − 1) + 4; n > 1

f(1) = 4 and f(n) = f(n − 1) + 2n; n > 1

f(1) = 2 and f(n) = f(n − 1) + 4n; n > 1

f(1) = 4 and f(n) = f(n − 1) + 2; n > 1
Mathematics
1 answer:
ra1l [238]4 years ago
5 0
The answer is the fourth option - <span>f(1) = 4 and f(n) = f(n − 1) + 2; n > 1
</span>
The first term is 4, So, f(1) = 4
The difference between two consecutive integer = 2, so, n = (n-1) + 2
It would be Option D) f(1) = 4 and f(n) = f(n − 1) + 2; n > 1

Hope this helps!
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Hey guys! Could someone help me with this problem? I got the wrong answer! The answer is B, but I don’t know how to get it! Coul
asambeis [7]
When it says 'which has a greater rate of change' it is referring to 'what has a greater slope.' So, let's calculate each thing's slope:

Table:
I'm going to pick the easiest values to work with, so I'll pick the points (0, -2) and (1, -9/5) - I simplified the mixed fraction. So, here we go, the slope formula is:
m =\frac{y_2-y_1}{x_2-x_1}
m = \frac{- \frac{9}{5} - (-2)}{1-0} = \frac{- \frac{9}{5} - ( -\frac{10}{5} )}{1-0}
m = \frac{ \frac{1}{5} }{1} = \frac{1}{5}

So, the table's slope is -1/5.

Graph
We can, again, pick two points. I'll pick the two given: (5, 0) and (0, -3).  Let's start off with the same formula:
m =\frac{y_2-y_1}{x_2-x_1}
m = \frac{-3-0}{0-5} = \frac{3}{5}

The graph's slope is 3/5.

Now, we just have to decide which is bigger: -1/5 or 3/5. So, clearly:
3/5 > -1/5. 

The 3/5 slope was the graph, hence it has the greater rate of change (that's why it's B). If anything doesn't make sense, feel free to DM me or ask!
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