Answer:
Solution given:
Since the given triangle is isosceles and right angled triangle
perpendicular [p]=base[b]=x
hypotenuse [h]=6
we have
by using Pythagoras law
p²+b²=h²
x²+x²=6²
2x²=36
x²=36/2
x²=18
x=
<u>x</u>=
Answer: angle 2 is supplementary to angle 1
10/12, 15/18, 20/24, 25/30, 30/36, 35/42, 40/48, 45/54, 50/60, and so on ...<span>
Source: </span><span>Equivalent fractions for 5/6</span>
First, let's see how 23 compares with the squares of the positive whole numbers on the number line.
1² = 1
2² = 4
3² = 9
4² = 16
5² = 25
The value of 23 is right between the square of 4 and the square of 5. Thus, the value √23 will be between 4 and 5.
Since 23 is much, much closer to the square of 5 than the square of 4, we can assume that the value √23 will be closer to 5 on the number line than 4.
Look at the attached image to see where I plotted the approximate location of √23.
You will realize that this approximation is pretty close since the actual value is roughly 4.80.
Let me know if you need any clarifications, thanks!
Answer:12
Step-by-step explanation:
Because I’m right anywhere