There's no way for me to do that, because my expression
is totally blank, and doesn't involve ' m ' in any way.
But if you'll come back and give us <u>your</u> expression, I'll
evaluate it for m=12, and I'll also show you how.
<h2>
Speed of plane = 1110 kmph</h2><h2>
Speed of wind = 150 kmph</h2>
Step-by-step explanation:
Let the speed of plane be p and speed of wind be w.
Flying against the wind, an airplane travels 5760 kilometers in 6 hours.
Here
Speed = (p-w) kmph
Time = 6 hours
Distance = 5760 kmph
Distance = Speed x Time
5760 = (p-w) x 6
p-w = 960 -----eqn 1
Flying with the wind, the same plane travels 6300 kilometers in 5 hours.
Here
Speed = (p+w) kmph
Time = 5 hours
Distance = 6300 kmph
Distance = Speed x Time
6300 = (p+w) x 5
p+w = 1260 -----eqn 2
eqn 1 + eqn 2
p-w + p +w = 960 + 1260
2p = 2220
p = 1110 kmph
Substituting in eqn 2
1110 + w = 1260
w = 150 kmph
Speed of plane = 1110 kmph
Speed of wind = 150 kmph
Answer:
8.06
Step-by-step explanation:
d=(−2−(−9))2+(3−7)2−−−−−−−−−−−−−−−−−−−√
d=(7)2+(−4)2−−−−−−−−−−√
d=49+16−−−−−−√
d=6–√5
d=8.062258
d=8.06
Answer:
i. 1.63 s
ii. The negative time cannot be used in this context
Step-by-step explanation:
i. Since h = −640t² and the rocket descends 1,690 m, h = -1,690 m (since there is a drop in height).
So, h = -640t²
t² = h/-640
t = √(- h/640)
Substituting h into the equation, we have
t = √(- h/640)
t = √[-(-1,690)/640]
t = √2.640625
t = 1.625
t ≈ 1.63 s
ii. So, the negative time cannot be used in this context because, the height drop is negative.
