You will see a tiny picture up top of the question and draw it out and added then work
Ok let me start it from here.
you are studying about properties of natural numbers or whole number or may be integers.
So , In this Question you have to follow property of addition of integers.
⇒7+3=( You are at the point 7 on the number line or on the tight rope , you are moving (+3) on the right direction.) So you will reach at 7+1+1+1=10
⇒4+2=( You are at the point 4 on the number line or on the tight rope , you are moving (+2) on the right direction.) So you will reach at 4+1+1=6
In first case Cecil has taken total walk of 10 units and in second case Cecil has taken a walk of 10 units.
Answer:
![P(X = 0) = 0.0263](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%200.0263)
![P(X = 1) = 0.1407](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%200.1407)
![P(X = 2) = 0.3012](https://tex.z-dn.net/?f=P%28X%20%3D%202%29%20%3D%200.3012)
![P(X = 3) = 0.3224](https://tex.z-dn.net/?f=P%28X%20%3D%203%29%20%3D%200.3224)
![P(X = 4) = 0.1725](https://tex.z-dn.net/?f=P%28X%20%3D%204%29%20%3D%200.1725)
![P(X = 5) = 0.0369](https://tex.z-dn.net/?f=P%28X%20%3D%205%29%20%3D%200.0369)
Step-by-step explanation:
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
And p is the probability of X happening.
In this problem we have that:
![n = 5, p = 0.517](https://tex.z-dn.net/?f=n%20%3D%205%2C%20p%20%3D%200.517)
Distribution
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![P(X = 0) = C_{5,0}.(0.517)^{0}.(0.483)^{5} = 0.0263](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20C_%7B5%2C0%7D.%280.517%29%5E%7B0%7D.%280.483%29%5E%7B5%7D%20%3D%200.0263)
![P(X = 1) = C_{5,1}.(0.517)^{1}.(0.483)^{4} = 0.1407](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20C_%7B5%2C1%7D.%280.517%29%5E%7B1%7D.%280.483%29%5E%7B4%7D%20%3D%200.1407)
![P(X = 2) = C_{5,2}.(0.517)^{2}.(0.483)^{3} = 0.3012](https://tex.z-dn.net/?f=P%28X%20%3D%202%29%20%3D%20C_%7B5%2C2%7D.%280.517%29%5E%7B2%7D.%280.483%29%5E%7B3%7D%20%3D%200.3012)
![P(X = 3) = C_{5,3}.(0.517)^{3}.(0.483)^{2} = 0.3224](https://tex.z-dn.net/?f=P%28X%20%3D%203%29%20%3D%20C_%7B5%2C3%7D.%280.517%29%5E%7B3%7D.%280.483%29%5E%7B2%7D%20%3D%200.3224)
![P(X = 4) = C_{5,4}.(0.517)^{4}.(0.483)^{1} = 0.1725](https://tex.z-dn.net/?f=P%28X%20%3D%204%29%20%3D%20C_%7B5%2C4%7D.%280.517%29%5E%7B4%7D.%280.483%29%5E%7B1%7D%20%3D%200.1725)
![P(X = 5) = C_{5,5}.(0.517)^{5}.(0.483)^{0} = 0.0369](https://tex.z-dn.net/?f=P%28X%20%3D%205%29%20%3D%20C_%7B5%2C5%7D.%280.517%29%5E%7B5%7D.%280.483%29%5E%7B0%7D%20%3D%200.0369)
7x=2+4
7x=6
X=6/7 ans
Hope you like it