Question

What is the equation of a line that passes through the point (-3, 1) and is parallel to a line with a slope of 2?

Answer 1

Slope-intercept form:  y = mx + b

[m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis]

For lines to be parallel, their slopes have to be the same.

Since you know:

m = 2       Then the parallel line's slope is also 2, so plug it into the equation

y = mx + b

y = 2x + b     To find b, plug in the point (-3, 1) into the equation

1 = 2(-3) + b

1 = -6 + b    Add 6 on both sides to get "b" by itself

1 + 6 = -6 + 6 + b

7 = b

y = 2x + 7          Your answer is D

Answer 2

Answer:

D. 2x + 7

Step-by-step explanation:

Use the point given, (-3, 1), and put it into the point-slope formula.

y - 1 = m(x+3)

The m, or the slope, is still blank. When you want a line parallel to a certain slope, the slope remains the same. Therefore, you plug in 2 for m:

y - 1 = 2(x+3)

y - 1 = 2x + 6

y = 2x + 7