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3 years ago

Extra points to the person who answer first

1 answer:

4 0

In order to know what is the reasonable amount of tile for Mandana to order, you have to divide the choices with the area of the floor and deduct with 1 and multiply by 100. You have to assess if the answer you will get will fall between 15% and 20% which is the goal of Mandana.

a. 131/116.9 = (1.1206 – 1) x 100 = 12.06%, this does not fall between 15% and 20%

b. 138/116.9 = (1.1805 – 1) x 100 = 18.05%, this fall between 15% and 20%

c. 133/116.9 = (1.1377 – 1) x 100 = 13.77%, this does not fall between 15% and 20%

d. 141/116.9 = (1.2062 – 1) x 100 = 20.62%, this does not fall between 15% and 20%

Therefore, the reasonable amount of tile for Madana to order that is between 15% and 20% extra of the materials is 138 square feet.

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How many real solutions does the system have? {y=−3x−3y=x2−3x+5

Daniel [21]

The answer is 0
I took the test and got it right i hope this helps someone

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3 years ago

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Dee has at most $150 to spend on restocking dolls and trains at her toy store. Dolls cost $7.50 and trains cost $5.00. Dee needs

Oliga [24]

Dolls = d
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I think is let that

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3 years ago

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Dane is investing $150,000 for 30 years at an annually compounded rate of 5.5%. What is the difference between his ending accoun

navik [9.2K]

Total = Principal × ( 1 + Rate )^years
Total = 150,000 * (1.055) ^ 30
Total = 150,000 * 4.9839512884
Total = 747,592.69

Total = 150,000 * (1.065) ^ 30
Total = 150,000 * 6.614366163 
Total = 992,154.92

Difference = 992,154.92 -747,592.69 =
244,562.23 

Source:
http://www.1728.org/compint.htm
online interest calculator

7 0

2 years ago

Given the length of three sides of a triangle, which is a right triangle?

RSB [31]

The aides of a right triangle will always satisfy the Pythagorean relationship ...

 a² + b²= c²

We can take each of these and try it out:

(1) ... 10² + 24² = 100 + 576 = 676
 √676 = 26 Yes.

(2) ... 12² + 18² = 144 + 324 = 468
 √468 = 21.6, not 20. No.

(3) ... 15² + 26² = 225 + 676 = 901
 √901 = 30.017 Awfully close. As an engineer, I'll buy this one. Yes.

(4) ... 40² + 50² = 1,600 + 2,500 = 4,100
 √4,100 = 64.03, not 80. No.

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2 years ago

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Help i dont understand how to complete this

Luda [366]

Answer: Josh = 19.8 hours, Danny = 10.8 hours

Step-by-step explanation:

$Josh: \dfrac{1}{x+9}\\\\\\Danny: \dfrac{1}{x}\\\\\\Together: \dfrac{1}{7}\\\\\\Josh\quad + \quad Danny\quad =\quad Together\\\dfrac{1}{x+9}\quad +\qquad \dfrac{1}{x}\qquad = \qquad \dfrac{1}{7}\\\\\\\underline{\text{Clear the denominator by multiplying by the LCM: (x+9)(x)(7)}}\\\\7(x) + 7(x+9)=x(x+9)\\7x + 7x + 63 = x^2+9x\\14x+63=x^2+9x\\0=x^2-5x-63\\\\\\\underline{\text{Use the quadratic formula to solve for x: }}x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-(-5)\pm \sqrt{(-5)^2-4(1)(-63)}}{2(1)}\\\\\\.\quad =\dfrac{5\pm\sqrt{25+252}}{2}\\\\\\.\quad =\dfrac{5\pm\sqrt{277}}{2}\\\\\\.\quad =\dfrac{5\pm 16.6}{2}\\\\\\x =\dfrac{5+16.6}{2}\qquad x=\dfrac{5-16.6}{2}\\\\\\x=\dfrac{21.6}{2}\qquad \qquad x=\dfrac{-11.6}{2}\\\\\\x=10.8 \qquad \qquad x=-5.8$

Since time cannot be negative, x=-5.8 is an extraneous solution (not valid) so x = 10.8

Josh: x + 9 --> 10.8 + 9 = 19.8

Danny: x --> 10.8

****************************************************************************************

2a) k = 9.45 & 0.55

2b) x = 3/2

2c) x = 2/3 (x = -1 is an extraneous solution so is not valid)

2d) No Solution (x = 1 is an extraneous solution so is not valid)

Here is the work for 2a. Follow this format for b, c, & d

$\dfrac{3}{k^2-8x+12}=\dfrac{k}{k-2}-\dfrac{4}{k-6}\\\\\text{Since the denominator cannot equal zero, then } k \neq2\ and\ k\neq6\\\text{If either of the solutions are 2 or 6, then that solution needs to be crossed out}\\\\\underline{\text{Clear the denominator by multiplying by the LCM: (k-2)(k-6)}}\\\\3 = k(k-6)-4(k-2)\\3=k^2-6k-4k+8\\0=k^2-10k+5\\\\\\\underline{\text{Use the quadratic formula to solve for k}}$

$x=\dfrac{-(-10)\pm \sqrt{(-10)^2-4(1)(5)}}{2(1)}\\\\\\.\quad =\dfrac{10\pm\sqrt{100-20}}{2}\\\\\\.\quad =\dfrac{10\pm\sqrt{80}}{2}\\\\\\.\quad =\dfrac{10\pm8.9}{2}\\\\\\x=\dfrac{10+8.9}{2}\qquad x=\dfrac{10-8.9}{2}\\\\\\x=\dfrac{18.9}{2}\qquad x=\dfrac{1.1}{2}\\\\\\x=9.45\qquad x=0.55\\\\\\\text{Both answers are valid!}$

8 0

3 years ago