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Evgen [1.6K]
3 years ago
14

Find the quotient 6 divided 27L 600 mL

Mathematics
1 answer:
Semenov [28]3 years ago
4 0

Answer:

217.391304 m-3

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8.2.38<br> Find the value of x.<br> * *<br> (Round to the nearest tenth as needed.)
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Answer:

Step-by-step explanation:

To the nearest tenth 8.238

=8.2 to the nearest tenth

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3 years ago
Solve the inequality 2.7 ≥ a + 3
Rainbow [258]

2.7 ≥ a + 3

a + 3 <= 2.7

a <= - 0.3

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3 years ago
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A baseball player had 4 hits in 8 games. At this rafe, how many hits will the baseball player have in the next 28 games?
NemiM [27]
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3 years ago
Sheila loves to eat chicken tenders. A small order comes with 5 chicken
aev [14]

Answer:  The required number of large order of chicken tenders is 5.

Step-by-step explanation:  Given that Sheila loves to eat chicken tenders. A small order comes with 5 chicken  tenders, and a large order comes with 8 chicken tenders.

Last month, Sheila ordered chicken tenders a total of 7 times. She received a total of 50 chicken tenders.

We are to find the number of large chicken tenders received by Sheila.

Let x and y represents the number of small orders and large orders respectively of chicken tenders.

Then, according to the given information, we have

x+y=7\\\\\Rightarrow x=7-y~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

and

5x+8y=50\\\\\Rightarrow 5(7-y)+8y=50~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{Using equation (i)}]\\\\\Rightarrow 35-5y+8y=50\\\\\Rightarrow 3y=50-35\\\\\Rightarrow 3y=15\\\\\Rightarrow y=\dfrac{15}{3}\\\\\Rightarrow y=5.

Thus, the required number of large order of chicken tenders is 5.

5 0
3 years ago
Solve 8n + 20 &lt; 6n + 24
antoniya [11.8K]

Answer:

  n < 2

Step-by-step explanation:

This inequality can be solved the same way the corresponding 3-step linear equation would be solved.

  8n +20 < 6n +24 . . . . . given

  2n +20 < 24 . . . . . . . . step 1, subtract 6n to isolate the variable on the left

  2n < 4 . . . . . . . . . . . . step 2, subtract 20 to separate constants and variable terms

  n < 2 . . . . . . . . . . . divide by the coefficient of the variable

4 0
2 years ago
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