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JulijaS [17]
3 years ago
8

Derek just purchased a new cube shaped fish tank.it holds 13,824 inches3 of water. What is the length of one of the sides?please

help!!!and on the other one if you can!:)11 points

Mathematics
1 answer:
Damm [24]3 years ago
7 0
The side of Derek's fish tank would measure out to be 2304 inches
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Algebra 1 A Adaptive CR (JL22) 1/Tools Of The Trade
Archy [21]

The simplified expression of (4^3)(\frac{4^4^0x^4}{3^2x^2y^2}) is \frac{4^7x^2}{3^2y^2}

<h3>How to simplify the expression?</h3>

The expression is given as:

(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})

Expressions raise to power 0 is 1.

So, we have:

(4^3)(\frac{4^4x^4}{3^2x^2y^2})

Apply the law of indices to expression with common base

(\frac{4^{4+3}x^{4-2}}{3^2y^2})

Evaluate the sum and difference

(\frac{4^7x^2}{3^2y^2})

Remove the bracket

\frac{4^7x^2}{3^2y^2}

Hence, the simplified expression of (4^3)(\frac{4^4^0x^4}{3^2x^2y^2}) is \frac{4^7x^2}{3^2y^2}

Read more about exponents at:

brainly.com/question/847241

#SPJ1

8 0
1 year ago
Three sets of data are given below. What is the
Tcecarenko [31]
The answer is C. 7
1.) take 8-(-3)
2.) 9-2
3.) 8-0
Then list the number in order least to greatest
-13 7 8
Find the middle number
Get 7
8 0
3 years ago
I just need no. a please help me to prove this. ​
OleMash [197]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    and         cos A = cos B · cos C

scratchwork:

  A + B + C = π

               A = π - (B + C)

         cos A = cos [π - (B + C)]                              Apply cos

                    = - cos (B + C)                                    Simplify

                    = -(cos B · cos C - sin B · sin C)          Sum Identity

                    = sin B · sin C - cos B · cos C               Simplify

cos B · cos C = sin B · sin C - cos B · cos C               Substitution

2cos B · cos C = sin B · sin C                                        Addition

                     2=\dfrac{\sin B\cdot \sin C}{\cos B \cdot \cos C}                                     Division

                     2 = tan B · tan C

\text{Use the Sum Identity:}\quad \tan(B+C)=\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}

<u>Proof LHS → RHS</u>

Given:                              A + B + C = π

Subtraction:                     A = π - (B + C)

Apply tan:                  tan A = tan(π - (B + C))

Simplify:                               = - tan (B + C)

\text{Sum Identity:}\qquad \qquad \qquad =-\bigg(\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}\bigg)

Substitution:                        = -(tan B + tan C)/(1 - 2)

Simplify:                               = -(tan B + tan C)/-1

                                            = tan B + tan C

LHS = RHS:   tan B + tan C = tan B + tan C  \checkmark

5 0
3 years ago
Which expressions are equivalent?
Hatshy [7]

Answer:

3(a-b) and 3a-3b. Equivalent

2a(2+b) and 4ab. Not equivalent

Step-by-step explanation:

hope this helps:)

6 0
3 years ago
Read 2 more answers
Tomasso’s family used 24.5 gallons of gas to drive 548.8 miles how many miles did they drive for gas?
Georgia [21]
22.4 miles for gas :]
3 0
3 years ago
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