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Jobisdone [24]
1 year ago
6

Algebra 2 unit 5 lesson 6 homework

Mathematics
1 answer:
kap26 [50]1 year ago
6 0

Through the addition and subtraction of the polynomial functions, g(x), f(x), and h(x), we have;

1. g(x) - k(x) = 6•x² - 3•x³ - 8•x + 8

2. h(x) + g(x) = 2•x² - x - 2

3. k(x) - g(x) = 3•x³ - 6•x² + 8•x - 8

4. h(x) - (g(x) + k(x)) = 2•x² - 3•x³ + 3

5. k(x)-g(x)+k(x)=6•x³- 10•x² + 13•x - 15

<h3>How can the expressions representing the polynomial functions be found?</h3>

The given functions are;

  • g(x) = 2•x² - 3•x + 1
  • h(x) = 2•x - 3
  • k(x) = 3•x³ - 4•x² + 5•x - 7

Which gives;

1. g(x) - k(x) = 2•x² - 3•x + 1 - (3•x³ - 4•x² + 5•x - 7) = 6•x² - 3•x³ - 8•x + 8

  • g(x) - k(x) = 6•x² - 3•x³ - 8•x + 8

2. h(x) + g(x) = 2•x - 3 + (2•x² - 3•x + 1) = 2•x² - x - 2

  • h(x) + g(x) = 2•x² - x - 2

3. k(x) - g(x) = 3•x³ - 4•x² + 5•x - 7 - (2•x² - 3•x + 1) = 3•x³ - 6•x² + 8•x - 8

  • k(x) - g(x) = 3•x³ - 6•x² + 8•x - 8

4. h(x) - (g(x) + k(x)) can be found as follows;

g(x) + k(x) = 2•x² - 3•x + 1 + 3•x³ - 4•x² + 5•x - 7 = 3•x³ - 2•x² + 2•x - 6

h(x) - (g(x) + k(x)) = 2•x - 3 - (3•x³ - 2•x² + 2•x - 6) = 2•x² - 3•x³ + 3

  • h(x)- (g(x) + k(x)) = 2•x² - 3•x³ + 3

5. k(x) - g(x) + k(x) = 3•x³ - 4•x² + 5•x - 7 - (2•x² - 3•x + 1) + 3•x³ - 4•x² + 5•x - 7 = 6•x³ - 10•x² + 13•x - 15

  • k(x)-g(x)+k(x)=6•x³-10•x²+13•x- 15

Learn more about polynomial functions here:

brainly.com/question/6948391

#SPJ1

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