1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Jobisdone [24]
2 years ago
6

Algebra 2 unit 5 lesson 6 homework

Mathematics
1 answer:
kap26 [50]2 years ago
6 0

Through the addition and subtraction of the polynomial functions, g(x), f(x), and h(x), we have;

1. g(x) - k(x) = 6•x² - 3•x³ - 8•x + 8

2. h(x) + g(x) = 2•x² - x - 2

3. k(x) - g(x) = 3•x³ - 6•x² + 8•x - 8

4. h(x) - (g(x) + k(x)) = 2•x² - 3•x³ + 3

5. k(x)-g(x)+k(x)=6•x³- 10•x² + 13•x - 15

<h3>How can the expressions representing the polynomial functions be found?</h3>

The given functions are;

  • g(x) = 2•x² - 3•x + 1
  • h(x) = 2•x - 3
  • k(x) = 3•x³ - 4•x² + 5•x - 7

Which gives;

1. g(x) - k(x) = 2•x² - 3•x + 1 - (3•x³ - 4•x² + 5•x - 7) = 6•x² - 3•x³ - 8•x + 8

  • g(x) - k(x) = 6•x² - 3•x³ - 8•x + 8

2. h(x) + g(x) = 2•x - 3 + (2•x² - 3•x + 1) = 2•x² - x - 2

  • h(x) + g(x) = 2•x² - x - 2

3. k(x) - g(x) = 3•x³ - 4•x² + 5•x - 7 - (2•x² - 3•x + 1) = 3•x³ - 6•x² + 8•x - 8

  • k(x) - g(x) = 3•x³ - 6•x² + 8•x - 8

4. h(x) - (g(x) + k(x)) can be found as follows;

g(x) + k(x) = 2•x² - 3•x + 1 + 3•x³ - 4•x² + 5•x - 7 = 3•x³ - 2•x² + 2•x - 6

h(x) - (g(x) + k(x)) = 2•x - 3 - (3•x³ - 2•x² + 2•x - 6) = 2•x² - 3•x³ + 3

  • h(x)- (g(x) + k(x)) = 2•x² - 3•x³ + 3

5. k(x) - g(x) + k(x) = 3•x³ - 4•x² + 5•x - 7 - (2•x² - 3•x + 1) + 3•x³ - 4•x² + 5•x - 7 = 6•x³ - 10•x² + 13•x - 15

  • k(x)-g(x)+k(x)=6•x³-10•x²+13•x- 15

Learn more about polynomial functions here:

brainly.com/question/6948391

#SPJ1

You might be interested in
How many groups of sixty are in two hundred forty four?
dedylja [7]
This is not going to be a hole number, it's about 4.0666
6 0
3 years ago
Read 2 more answers
What is the equation in point-slope form of the line passing through (4, 0) and (2, 6)? (5 points) y = 4x − 2 y = 2x − 4 y = −3(
DIA [1.3K]

For this case we have that by definition, the point-slope equation of a line is given by:

y-y_ {0} = m (x-x_ {0})

We have the following points:

(x_ {1}, y_ {1}) :( 2,6)\\(x_ {2}, y_ {2}) :( 4,0)\\m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {0-6} {4-2} = \frac {-6} {2} = -3

We chose a point:

(x_ {0}, y_ {0}) :( 4,0)

Substituting in the equation we have:

y-0 = -3 (x-4)\\y = -3 (x-4)

Finally, the equation is: y = -3 (x-4)

Answer:

OPTION C

6 0
3 years ago
Read 2 more answers
Whats 2x + y = 10 5x - y = 18 in elimination method
Naya [18.7K]
2x + y = 10
5x - y = 18

7x = 28

x = 4

2(4) + y = 10

8 + y = 10

y = 2

(4,2)
8 0
3 years ago
This equation shows how the revenue at Jill's Auto Wash depends on the number of
Romashka [77]

Answer:y = 9x

Step-by-step explanation:

6 0
2 years ago
Is 9/11 rounded to 0,1/2 or 1
uranmaximum [27]
9/11 is rounded to 1. It rounds up because 9 is higher than 5, which is the middle of 11.
4 0
3 years ago
Read 2 more answers
Other questions:
  • Dilation ( effects of changing dimensions on perimeter and area)
    10·1 answer
  • Find the quotient of -36/12. A)3 B)18 C)24 D)-3
    8·1 answer
  • Median and range of 11,17,19,6,17
    8·1 answer
  • Beer shelf life is a problem for brewers and distributors because when beer is stored at room temperature, its flavor deteriorat
    13·1 answer
  • What is the prime factorization of 44?
    5·2 answers
  • Hyhhgubbvfyvvjijbb hhguhvgy. Vvgghhbg. Hyhvghh bhggh
    12·2 answers
  • The sum of 10 and Hector's age is 69 . Use the variable H to represent Hector's age.
    5·1 answer
  • ,<br> If x=y and y = 18, what is the value of 2x-3?<br> 3<br> A) 21<br> B) 15<br> C) 12<br> D) 10
    8·1 answer
  • There 7 ducklings .they sleep in 1 large nest .write and solve an equation that shows how many ducklings sleep in the nest
    10·2 answers
  • The company is going to choose three rows in each section to win the hats. There are
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!