Answer:
I think what you meant to say is "If a triangle has 2 sides that are 4 cm and 20 cm, what are the possible lengths of the third side?"
Basically, when given 2 sides of a triangle, the third side must be GREATER than the DIFFERENCE of the other 2 sides and LESS than the SUM of the other 2 sides.
difference = 16 cm
sum = 24 cm
So, the third side must be greater than 16 cm and less than 24 cm
Step-by-step explanation:
You round down so 2.3 goes to 2
We have that
y=x²----> equation 1<span>
y=x+2-----> equation 2
multiply equation 1 by -1
-y=-x</span>²
add equation 1 and equation 2
-y=-x²
y=x+2
------------
0=-x²+x+2-------------> -x²+x+2=0-----> x²-x-2=0
Group terms that contain the same variable, and move the
constant to the opposite side of the equation
(x²-x)=2
<span>Complete
the square. Remember to balance the equation by adding the same constants
to each side
</span>(x²-x+0.5²)=2+0.5²
Rewrite as perfect squares
(x-0.5)²=2+0.5²
(x-0.5)²=2.25-----> (x-0.5)=(+/-)√2.25-----> (x-0.5)=(+/-)1.5
x1=1.5+0.5-----> x1=2
x2=-1.5+0.5---- > x2=-1
for x=2
y=x²----> y=2²----> y=4
the point is (2,4)
for x=-1
y=x²----> y=(-1)²---> y=1
the point is (-1,1)
the answer isthe solution of the system are the points(2,4) and (-1,1)
Multiple 11/25 with 4 and 9/20 with 5 so it will be
44/100 and 45/100
