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nasty-shy [4]
3 years ago
9

Which of the following expressions is equivalent to −8x ?

Mathematics
1 answer:
levacccp [35]3 years ago
3 0

Answer:

D

Step-by-step explanation:

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What is the surface area of a cube with faces that each have an area of 16 cm2?
OleMash [197]
I believe the answer is A. I'm not too sure though. How did I come to this conclusion? ¯\_(ツ)_/¯
3 0
3 years ago
the highest of three cylinders are 3 cm 9 cm and 5 cm if the cylinder has a capacity of 725 calculate the capacitance of the oth
Allushta [10]

The capacitance of the other cylinders are 2174. 94cm³ and 1208. 30cm³.

<h3>How to find the capacitance</h3>

Capacity of a cylinder is seen as its volume

Volume of a cylinder = πr²h

The heights of the cylinders are

a. 3cm

b. 9cm

c. 5cm

Let's find the radius

Capacity = 3. 142 × r² × 3

725 = 3. 142 × r² × 3

r² = \frac{725}{3. 142 * 3}

r² = \frac{725}{9. 426}

r² = 76. 91

r = √76. 91

r = 8. 77cm

Radius of the cylinders = 8. 77cm

For cylinder with height of 9cm

Capacitance = πr²h

Capacitance = 3. 142 × 8. 77 × 8. 77 × 9

Capacitance = 2174. 94 cm³

For cylinder with height of 5cm

Capacitance = 3. 142 × 8. 77 × 8. 77 × 5

Capacitance = 1208. 30 cm³

Thus, the capacitance of the other cylinders are 2174. 94cm³ and 1208. 30cm³.

Learn more about volume of a cylinder here:

brainly.com/question/9554871

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6 0
2 years ago
PLZZZZZZZZZZZZZZZZZ HELP!
Svet_ta [14]

answer: -5x+12=20

                   -12    -12

            -5x/-5= 8/-5

             x= -1.6

       Check: rewrite the orignal problem

          plug your variable

       

             

5 0
3 years ago
Compute the surface area of the portion of the sphere with center the origin and radius 4 that lies inside the cylinder x^2+y^2=
Tom [10]

Answer:

16π

Step-by-step explanation:

Given that:

The sphere of the radius = x^2 + y^2 +z^2 = 4^2

z^2 = 16 -x^2 -y^2

z = \sqrt{16-x^2-y^2}

The partial derivatives of Z_x = \dfrac{-2x}{2 \sqrt{16-x^2 -y^2}}

Z_x = \dfrac{-x}{\sqrt{16-x^2 -y^2}}

Similarly;

Z_y = \dfrac{-y}{\sqrt{16-x^2 -y^2}}

∴

dS = \sqrt{1 + Z_x^2 +Z_y^2} \ \ . dA

=\sqrt{1 + \dfrac{x^2}{16-x^2-y^2} + \dfrac{y^2}{16-x^2-y^2} }\ \ .dA

=\sqrt{ \dfrac{16}{16-x^2-y^2}  }\ \ .dA

=\dfrac{4}{\sqrt{ 16-x^2-y^2}  }\ \ .dA

Now; the region R = x² + y² = 12

Let;

x = rcosθ = x; x varies from 0 to 2π

y = rsinθ = y; y varies from 0 to \sqrt{12}

dA = rdrdθ

∴

The surface area S = \int \limits _R \int \ dS

=  \int \limits _R\int  \ \dfrac{4}{\sqrt{ 16-x^2 -y^2} } \ dA

= \int \limits^{2 \pi}_{0} } \int^{\sqrt{12}}_{0} \dfrac{4}{\sqrt{16-r^2}} \  \ rdrd \theta

= 2 \pi \int^{\sqrt{12}}_{0} \ \dfrac{4r}{\sqrt{16-r^2}}\ dr

= 2 \pi \times 4 \Bigg [ \dfrac{\sqrt{16-r^2}}{\dfrac{1}{2}(-2)} \Bigg]^{\sqrt{12}}_{0}

= 8\pi ( - \sqrt{4} + \sqrt{16})

= 8π ( -2 + 4)

= 8π(2)

= 16π

4 0
3 years ago
Write the product in standard form. ( 4 + 7i)( 7 + 7i)
Helen [10]
The answer is a) -21 - 77i
7 0
4 years ago
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