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klio [65]
3 years ago
15

Please Please Help Me In These Math Questions!!!!’

Mathematics
1 answer:
Harman [31]3 years ago
6 0

Answer:

m∠JLN = 42°

m∠MLK = 90°

m∠KLO = 42°

m∠JLO = 138°

m∠AGE = 160°

Step-by-step explanation:

m∠JLN = 90-48=42°

m∠MLK = 90°

m∠KLO = 42° (∠KLO opposite of ∠JLN, Opposite angles are congruent)

m∠JLO = 180-42=138°

For the second question, things become somewhat more complex.

We know that ∠GHD = 2x° and ∠AGH (x+15)°.

You correctly calculated that x=15°.

∠AGE is equal to both 180-(x+15)° and 180-2x°. Either equation will work just fine.

∠AGE = 180 - (15 + 15) = 180 - 30 = 160°

So m∠AGE = 160°

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2 years ago
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Answer:

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average = --------------------------------

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Here we know that the average mark was 68, so we can write:

               

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average = 68 = ----------------------------------

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Solving for x, we multiply both sides by 5:     340 = 274 + x.

Subtracting 274 from both sides effectively isolates x:

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------------------------

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The fifth student's mark was 66.

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