Answer:
40951
Step-by-step explanation:
Using the principles of inclusion - Exclusion
Where C(n,r)=n!/(n-r)!r!
Total elements in the five sets including number repetition is given as (10000)×C(5, 1) =10000× 5!/(5-1)!1!=10000×5=50000
Total Number of elements in each pair including number repetition of sets is given as
=(1000) × C(5, 2) =10000
Number of elements in each triple of sets is given as
=(100) × C(5, 3) =1000
Number of elements in every four sets
=(10) × C(5, 4)=50
Number of elements in every one set
(1) × C(5, 5)=1
Therefore total number of unique elements=50000-10000+1000-50+1
=40951
To find 10,000 more than 6,310, you add; so the answer is 16,310
false becasue 11,12,13,14,15,16,17,18,19,20,21, and 22 is bigger and 111,112,113,114,115,116,117,118,119,120,121, and 122 is smaller.
1. SAS
2. SSS
3. SAS
4. AAS
5. SAS
6. SAS
7. AAS
8. ASA
9. SSS
Answer:
97
Step-by-step explanation:
Do 150 divided by 20 which is 7.5 then do 13 x 7.5 which is 97.5 BUT you cant win 97.5 times do I believe that it would be 97 (if that's not an option, do 98)
