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3 years ago

15

When Andrew goes bowling, his scores are normally distributed with a mean of 115 and a standard deviation of 11. What is the pro

bability that the next game Andrew bowls, his score will be between 86 and 106, to the nearest thousandth?

1 answer:

Masteriza [31]3 years ago

7 0

Answer:

I have no idea. : /

Step-by-step explanation:

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Evaluate the given expression if x = 25, y = 10, w = 11, and z = 18.<br><br> (see the image)

hammer [34]

Answer:

D

Step-by-step explanation:

So we have the expression:

$(x-y)^2+10wz$

And we want to evaluate it when x=25, y=10, w=11, and z=18.

So, substitute these values for the variables:

$=(25-10)^2+10(11)(18)$

First, subtract within the parentheses:

$=(15)^2+10(11)(18)$

Square 15:

$=225+10(11)(18)$

Now, multiply the terms on the right. 10 times 11 is 110:

$=225+110(18)$

Multiply:

$=225+1980$

Finally, add:

$=2205$

So, our answer is D.

And we're done!

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