Since it is a parallelogram cente at point T,
then the measure of PT is equal to the measure of TR. And the measure of QT is
equal to the measure of TS.
PT = TR
a + 4 = 2a
4 = 2a -a
a = 4
PT = TR = 8 units
QT = TS
b = 2b -3
3 = 2b – b
b = 3
<span>QT = TS = 3 units</span>
(2x/-5x)+x^2
(x(2)/(x(-5))+x^2
(-2/5)+x^2, the x values cancel in numerator and denominator and simplify to -2/5
The answer is 0.125....................................
Answer: f(-6) =
, f(-4) =
, f(4) =
, f(6) = 
<u>Step-by-step explanation:</u>
(-6, f(-6)) is an x,y coordinate. They are asking what the y-value is when you plug in -6 for x.
f(x) = 
f(-6) = 
= 
= 
f(-4) = 
= 
= 
= 
f(4) = 
= 
= 
= 
f(6) = 
= 
= 