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VLD [36.1K]
2 years ago
11

Which word problem matches the inequality

Mathematics
1 answer:
ira [324]2 years ago
8 0

.........................................

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What is the measurement of the highlighted side x? Please help and show steps please :)
Soloha48 [4]

Answer:

Denote the O, A, B, C, D as shown in attached image:

O is center of circle.

OA = OC = OD = radius of circle

=> triangle OAD is isosceles

=> BA = BD = 12.8

Applying Pythagorean theorem:

OB = sqrt(OA^2 - BA^2) = sqrt(15.1^2 - 12.8^2) = 8.0

=> x = OC - OB = 15.1 - 8.0 = 7.1

Hope this helps!

:)

8 0
3 years ago
Necesito resolver esta ecuación de segundo grado:<br> x^{2} =x
ch4aika [34]

Answer:

x = 0 , 1

Step-by-step explanation:

x² = x

x² - x = 0

x ( x-1 ) = 0

x=0 and x=1

6 0
3 years ago
PLEASE HELP what is the perimeter of ABC? round each step to the nearest tenth.
nikitadnepr [17]

the perimeter is 18.7 units

4 0
3 years ago
Hello please help i’ll give brainliest
Kamila [148]

Answer:

i think 8

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
In a certain school 70% of the students in first-year chemistry have had algebra. If there are 290 students in first-year chemis
KiRa [710]

The number of the students in the school that have had algebra is 203

<h3>How to determine the number of students?</h3>

The given parameters in the question are

  • Proportion of students taking algebra, p = 70%
  • Number of students in the school, n = 290

The number of students that had algebra in the school is calculated as:

Algebra = Proportion of students taking algebra * Number of students in the school

The above equation can be represented as:

Algebra = np

Substitute values for n and p in the above equation

So, we have

Algebra = 290 * 70%

Express 70% as decimal i.e. 0.70

So, we have

Algebra = 290 * 0.70

Evaluate the product i.e. multiply 290 and 0.70

So, we have

Algebra = 203

Hence, the number of the students in the school that have had algebra is 203

Read more about expected values at:

brainly.com/question/15858152

#SPJ1

8 0
1 year ago
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