If f(x)=x^4+3x^3-x^2+6, find f(-3).

Mathematics

1 answer:

docker41 [41]3 years ago

4 0

Answer:

f(-3) = -3

Step-by-step explanation:

Step 1: f(x) means "f of x" and f(-3) means "f of -3", so you have to replace all the "x" letters in the function with the value -3.

$f(x)=x^4+3x^3-x^2+6\\f(-3)=(-3)^4+3(-3)^3-(-3)^2+6$

Step 2: Apply the exponents. <em>Make sure you remember to put in the -3 and not just 3.</em>

$f(-3)=81+3(-27)-9+6$

Step 3: Use BEDMAS rules to complete the calculation.

$f(-3)=81-81-9+6$

$f(-3)=-3$

Therefore the answer is f(-3) = -3.

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