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charle [14.2K]
3 years ago
8

A ship sails 30.50 mi due East and then turns 33.75 north of East. After sailing another 18.53 mi, where is it with reference to

the starting point

Mathematics
1 answer:
Vladimir [108]3 years ago
6 0

A ship sails 30.50 mi due East and then turns 33.75 degree north of East. After sailing another 18.53 mi, where is it with reference to the starting point

<u>Answer:</u>

The ship is 18.269 miles distance north of east from starting point

<u>Solution:</u>

Given that ship sails 30.50 miles east

North of east = 18.53 miles

Angle between two sides = 33.75 degree

The figure is attached below

In the figure, A represents starting point

AB = c represents the ship distance with reference to starting point

By using law of cosines,

c^{2}=a^{2}+b^{2}-2 a b \cos c

c^{2}=(30.50)^{2}+(18.53)^{2}-2(30.50)(18.53) \cos 33.75

c^{2}=930.259+343.3609-939.835

\begin{aligned} c^{2} &=333.7849 \\\\ c &=\pm 18.269 \end{aligned}

Ignore negative value as we measure distance in positive

c = 18.269

It is 18.269 miles distance north of east from starting point

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