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mash [69]
3 years ago
5

57 61 50 54 54 54 56 54 61 54 48 49 42 51 61 57 68 65 50 51 60 52 57 51 52 47 56 62 69 58 49 56 55 55 43 64 57 64 46 55 51 55 46

Mathematics
2 answers:
uranmaximum [27]3 years ago
7 0
What exactly is the question?

siniylev [52]3 years ago
4 0

Answer:

What is the question

Step-by-step explanation: 23 45 67 89 90 78 56 45 67 54 34 43 21 212 12 34 5 6 80 90 87 65 56 78 78 98 89 28 92 19 10 20 30 40 50 60 70 80 90 100 10 9 8 7 6 5 4 3 2 1

Good luck

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The age of some lecturers are 42,54,50,54,50,42,46,46,48 and 48 calculate the mean age and standard deviation
rjkz [21]

Answer:

Mean age: 48

Standard deviation: 4

Step-by-step explanation:

a) Mean

The formula for Mean = Sum of terms/ Number of terms

Number of terms

= 42 + 54 + 50 + 54 + 50 + 42 + 46 + 46 + 48+ 48/ 10

= 480/10

= 48

The mean age is 48

b) Standard deviation

The formula for Standard deviation =

√(x - Mean)²/n

Where n = number of terms

Standard deviation =

√[(42 - 48)² + (54 - 48)² + (50 - 48)² +(54 - 48)² + (50 - 48)² +(42 - 48)² + (46 - 48)² + (46 - 48)² + (48 - 48)² + (48 - 48)² / 10]

= √-6² + 6² + 2² + 6² + 2² + -6² + -2² + -2² + 0² + 0²/10

=√36 + 36 + 4 + 36 + 4 + 36 + 4 + 4 + 0 + 0/ 10

=√160/10

= √16

= 4

The standard deviation of the ages is 4

3 0
4 years ago
Two increased by the product of a number and 9 is greater than or equal to 25.
Marianna [84]

Answer:

x≥2.56

Step-by-step explanation:

first we can write the inequality

2+9x≥25

we can now solve this with algebra

9x≥23

x≥2.56

3 0
3 years ago
Find the indicated function value for csc -450°
Mekhanik [1.2K]

Step-by-step explanation:

\csc( - 450 \degree) \\  \\  =  -  \csc450 \degree \\  \\  =  -  \csc(360 \degree + 90\degree) \\  \\  = -  \csc( 90\degree) \\  \\  =  - 1

4 0
3 years ago
Solve for slope y intercept and the equation please ​
aliya0001 [1]

Answer:

y=x-5 slope=1 y-intercept=-5

Step-by-step explanation:

5 0
3 years ago
What’s the answer. Please respond fast
8_murik_8 [283]
The answer to your problem is 108.18
7 0
3 years ago
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