Find percentage of each quantity. 40% of an hour In hours and minutes

andre [41]

Answer:

D

Step-by-step explanation:

I tried all the other equations by plugging in numbers and disproving their accuracy. D was the only one that worked.

4 0

3 years ago

A can of drink is in the shape of a cylinder. The can has a radius of 4cm and a height of 15cm. Calculate the volume of the cyli

yan [13]

The volume of a cylinder is

Volume = π (radius)² (length or height)

Volume = π (4 cm)² (15 cm) = 240 π cm³ = 753.98 cm³

6 0

3 years ago

Read 2 more answers

I need help with this question

kaheart [24]

Answer:

your answer is 7x square root ÷ 3/90

3 0

4 years ago

Psychology students at Wittenberg University completed the Dental Anxiety Scale questionnaire (Psychological Reports, August 199

fredd [130]

Answer:

a) $Z = 1.43$

b) There is a 48.696% probability that someone scores between a 10 and a 15 on the Dental Anxiety Scale is

Step-by-step explanation:

Normal model problems can be solved by the zscore formula.

On a normaly distributed set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a value X is given by:

$Z = \frac{X - \mu}{\sigma}$

Each z-score value has an equivalent p-value, that represents the percentile that the value X is.

In our problem, the mean score was 11 and the standard deviation was 3.5.

So, $\mu = 11$ , $\sigma = 3.5$ .

(a) Suppose you score a 16 on the Dental Anxiety Scale. Find the z-value for this score.

What is the value of Z when $X = 16$ ?

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{16 - 11}{3.5} = 1.43$

(b) Find the probability that someone scores between a 10 and a 15 on the Dental Anxiety Scale.

We have to find the percentiles of both of these scores. This means that we have to find Z when $X = 10$ and $X = 15$ . The probability that someone scores between a 10 and a 15 is the difference between the pvalues of the z-value of X = 10 and X = 15.

When $X = 10$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{10 - 11}{3.5} = -0.29$

Looking at the z score table, we find that the pvlaue of $Z = -0.29$ is 0.3859.

When $X = 15$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{15 - 11}{3.5} = 1.14$

Looking at the z score table, we find that the pvlaue of $Z = 1.14$ is 0.87286.

So, the probability that someone scores between a 10 and a 15 on the Dental Anxiety Scale is

0.87286 - 0.3859 = 0.48696 = 48.696%

(c) Find the probability that someone scores above a 17 on the Dental Anxiety Scale

This probability is 100% minus the pvalue of the zvalue when $X = 17$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{17 - 11}{3.5} = 1.71$

When $Z = 1.71$ , the pvalue is 0.95637. This means that there is a 95.637% probability that someone scores BELOW 17 on the dental anxiente scale.

100 - 95.637 = 4.363%

There is 4.363% probability that someone scores above a 17 on the Dental Anxiety Scale

4 0

3 years ago

What is opportunity sampling

Yakvenalex [24]

Answer:

Opportunity sampling is also known as convenience and it can be defined as a sampling technique which typically involves the process of selecting participants from a population of interest (target group) to take part in a research study.

Step-by-step explanation:

In Statistics, sampling can be defined as a process used to collect or select data (objects, observations, or individuals) from a larger statistical population using specific procedures.

There are various types of sampling used by researchers and these are;

1. Random sampling.

2. Systematic sampling.

3. Stratified sampling.

4. Cluster sampling.

5. Opportunity or convenience sampling.

Opportunity sampling is also known as convenience and it can be defined as a sampling technique which typically involves the process of selecting participants from a population of interest (target group) to take part in a research study.

This ultimately implies that, an opportunity sampling is a non-probability sampling in which a researcher select participants based on their availability for the study.

For example, John a psychologist standing on the street requesting that passersby join in his research study.

6 0

3 years ago