Concluimos que a partir de 21 piezas se gana más en la empresa B.
<h3>
¿Cuanto debe vender para que le paguen más en la empresa B?</h3>
Si definimos el número de piezas vendidas como x, la cantidad que le pagan en la empresa A es:
A(x) = $6000 + $20*x
Y lo que le pagan en la empresa B es:
B(x) = $6000 + x^2
Queremos ver para que valor de x, se da que B(x) > A(x).
Entoces resolvamos esa inequación.
6000 + 20*x < 6000 + x^2
20x < x^2
20 < x
x debe ser más grande que 20, entonces concluimos que a partir de 21 piezas se gana más en la empresa B.
Sí quieres aprender más sobre inecuaciones, puedes leer:
brainly.com/question/23023694
1/5 since your choosing 1 dvd out of 5
and then assuming you DONT put season one back on the shelf you would then have the probablity of 1/4 because you are again choosing 1 dvd out of now 4
Step-by-step explanation:
We are asked to write a system of equations using our given information.
Let x be number of small dogs and y be number of large dogs.
We have been given that paws at play made a total of $1,234 grooming 22 dogs, which means that number of small dogs and large dogs is 22. We can represent this information as:
We have been given that paws at play charges $43 to groom each small dog and $75 for each large dog. So the total grooming charges for grooming x small and y large dogs will be 43x+75y, that is equal to total charges for grooming $1234.
We can represent this information as:

Therefore, our desired system of equations is:
5km = 5000m = 50000cm
thus, 50000:450 then simpify it. the final answer would be 1000:9