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3 years ago

Solve the equation for x. 18=6(2– 8)

Mathematics

1 answer:

Julli [10]3 years ago

4 0

Answer:

5.5

Step-by-step explanation:

18 = 6(2x - 8)

18/6 = 2x - 8

3 = 2x - 8

2x = 11

x = 11/2 or 5½

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Help on this problem pls<br> Thanx

maw [93]

5/7 +1/3

find the common denominator for both of the fractions

common denominator is 21

mutiply by 3 for 5/7

(5)(3)/(7/(3)= 15/21

mutiply by 7 for 1/3

(1)(7)/(3)(7)= 7/21

15/21+7/21

add the numerators

15+7= 22

denominator stays the same -21

Answer:

22/21 or 1 1/21

3 0

3 years ago

Someone please help me!!!!11

serious [3.7K]

The U stands for union. Combine A and B

Hope that helps!!

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3 years ago

How do you Simplify 12/90?

ladessa [460]

You can divide both numbers by 6 to get 2/15 (which cannot be simplified anymore)
2/15 is the simplified form

7 0

3 years ago

Read 2 more answers

raj and his sister zia are both at secondary school. Raj is three years older than zia. the sum of the squares of their ages is

Cerrena [4.2K]

Let Zia's age be = x years

Raj is three years older than Zia, so Raj's age = x+3 years

As the sum of the squares of their ages is 369, so

$x^{2}+(x+3)^{2}=369$

$x^{2}+x^{2}+6x+9=369$

$2x^{2}+6x+9=369$

$2x^{2}+6x-360=0$

Factoring 2 out we have,

$x^{2}+3x-180=0$

Now solving this equation,

$x^{2}+15x-12x-180=0$

$x(x+15)-12(x+15)$

$(x+15)(x-12)$

x=-15 and x=12

Neglect the negative value as x cannot be negative

So x=12

Hence, Zia's age is 12 years and

Raj's age is 12+3 = 15 years

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3 years ago

Three consecutive odd integers have a sum of 39 find the integers

Tema [17]

11 13 and 15 are the three odd integers

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3 years ago