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laila [671]
3 years ago
8

Can you give me a long list of kid's cartoons

Computers and Technology
2 answers:
Delicious77 [7]3 years ago
8 0
SpongeBob, Teen Titan Go, Future Worm. That's all I can think!
Nezavi [6.7K]3 years ago
6 0
Spongebob, Ben 10, Dog&Cat, The Rugrats, Ed, Ed, & Eddy, The Flintstones, The Jetsons, Tom & Jerry, Looney Toons, Popeye, Top cat, Pink Panther... 
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It’s true because the optimization is the software that cleans up the fragments in a hard drive.
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What is the theory of trouble shooting
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Answer:

Possibly the most important but hard-to-learn ability any technical individual might have is the gift to troubleshoot. For persons who are new with the expression, troubleshooting is the act of investigating and rectifying problems in any type of system. For a businessman, this might mean recognizing the source(s) of ineffectiveness in a business and suggesting a remedial course. For a doctor, this would mean accurately identifying a patient's trouble and recommending a treatment.

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You are hired by a game design company and one of their most popular games is The Journey. The game has a ton of quests, and for
Kamila [148]

Answer:

Explanation:

Let's describe the connected part for the very first time.

Component with good connections:-

A semi in any graph 'G' is defined by a way to align element if this can be crossed from the beginning of any link in that pixel or if this can be stated that there is a path across each organized node pair within this subgram.

Consecrated pair means (ni, nj) and (nj, ni) that 2 different pairs would be regarded.

In point a:

We're going to be using contradictions for this segment. They start with the assumption that two lucky journeys are not even in the same strongly interconnected component.

For instance, qi and qj are providing special quests that were not in the very strongly linked element and which implies that, if we start to cross from qi or qi, then qj cannot be approached if we begin to move through qj and as we established if qi or qj is fortunate contests, we may reach any other hunts. Which implies qj from qi or conversely should be reachable. Or we might claim that qi is part of the strongly linked portion of qj or vice versa with this situation.

Consequently, we would not be capable of forming part of a different and strongly linked element for two successful scientists; they must have the same strongly related to the element.

In point b:

Its definition of its strong, line segment indicates that all other searches within such a strongly coordinate system can be made possible from any quest. Because if all quests are accessible from any quest then a lucky search is named, and all other quests can be accessed from any quest in a very coordinated system. So, all contests are fortunate contests in a strongly connected element.

Algorithm:

Build 'n' size range named 'visited' wherein 'n' is the number of graphic nodes that keep records of nodes already frequented.  Running DFS out of every unknown vertex or mark all edges as seen.  The lucky search will be the last unexplored peak.

Psuedo-Code:

Requires this functionality to also be called Solution, it requires 2 reasons as an input, V is a set of objects in graph 'G' and 'G' is a chart itself.

Solution(V, G):

visited[V] = {false}//assign value

for v: 0 to 'V'-1:  //using for loop

if not visited[v]:  //use if block

DFS(v, visited, V, G)  //use DFS method

ans = v //holding value

return ans //return value

3 0
3 years ago
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Does Buzz or APEX shows all your due assignments on the left of the main home screen?
Sergeeva-Olga [200]

Answer:

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3 0
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What will be the output of the following code? <?php $foo = 'Bob'; $bar = $foo; $bar = "My name is $bar"; print $bar; print $
SCORPION-xisa [38]

Answer: b. My name is BobBob

Explanation:

  • $foo = 'Bob'; // Assigns foo variable the value Bob
  • $bar = $foo; // Assigns the value of foo to bar
  • $bar = "My name is $bar"; //changes the $bar this is the way to  include variables directly in the string.
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  • print $foo; // prints another Bob
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3 years ago
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