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Anika [276]
3 years ago
12

A skyscraper is 396 meters tall. At a certain time of day, it casts a shadow that is 332 meters long. At what angle is the sun a

bove the horizon at that time?

Mathematics
2 answers:
Reptile [31]3 years ago
6 0
I believe it would be 50 degrees 
vladimir2022 [97]3 years ago
6 0

Answer:

<em>The sun is at an angle of </em><em>50.02°</em><em> above the horizon at that time.</em>

Step-by-step explanation:

A skyscraper is 396 meters tall. At a certain time of day, it casts a shadow that is 332 meters long.

From the given attachment, in the right angled triangle ABC, AC is the skyscraper and BC is its shadow.

The angle that the sun is above the horizon is the angle of elevation or ∠B.

We know that,

\tan \theta=\dfrac{p}{b}

Putting the values,

\Rightarrow \tan B=\dfrac{AC}{BC}

\Rightarrow \tan B=\dfrac{396}{332}

\Rightarrow B=\tan^{-1}\dfrac{396}{332}

\Rightarrow B=50.02^{\circ \:}


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solniwko [45]
4x^2(2x+1)-9(2x+1)=0
(4x^2-9)(2x+1)=0
(2x-3)(2x+3)(2x+1)=0
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3 years ago
Please help me ASAP!Please this is due soon and i don't have all day.
Helga [31]

<u><em>Answer:</em></u>

Section 1: 5.59%

Section 2: -2.16%

Section 3: -10.82%

Section 4: -6.54%

Section 5: -2.16%

Section 6: 7.86%

<u><em>Explanation:</em></u>

<u>The formula to calculate the percent change in mass is given as:</u>

PercentChange = \frac{ChangeInMass}{StartingMass}*100=\frac{NewMass - OldMass}{OldMass}*100

<u>1- Section 1:</u>

Old mass = 7.83 g and New mass = 8.268 g

PercentChange = \frac{8.268-7.83}{7.83}*100 =5.59%

<u>2- Section 2:</u>

Old mass = 7.4 g and New mass = 7.24 g

PercentChange = \frac{7.24-7.4}{7.4}*100 =-2.16%

<u>3- Section 3:</u>

Old mass = 7.3 g and New mass = 6.51 g

PercentChange = \frac{6.51-7.3}{7.3}*100 =-10.82%

<u>4- Section 4:</u>

Old mass = 7.49 g and New mass = 7.0 g

PercentChange = \frac{7.0-7.49}{7.49}*100 =-6.54%

<u>5- Section 5:</u>

Old mass = 7.4 g and New mass = 7.24 g

PercentChange = \frac{7.24-7.4}{7.7.4}*100 =-2.16%

<u>6- Section 6:</u>

Old mass = 7.89 g and New mass = 8.51 g

PercentChange = \frac{8.51-7.89}{7.89}*100 =7.86%

Hope this helps :)

6 0
3 years ago
(due by 9)<br> n-43=5<br> Solve for n, and show your work
omeli [17]

Answer:

n=48

Step-by-step explanation:

  1. add 48 to both sides to get rid of it
  2. 43+5=48
  3. n=48
8 0
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Which best describes the resulting three-dimensional
Harman [31]

Answer: C

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How do you do this? Please help
PtichkaEL [24]

Answer:

PO=86.2\\ OM=23.8\\

Step-by-step explanation:

To preface, your figure is going to be a line segment, with O as your midpoint, in between points P & M.

With that being said:

PO+OM=PM

Identify your values:

PO=7y+12\\OM=3y-8\\PM=110

Substitute the values into the first equation:

7y+12+3y-8=110

Combine like terms:

10y+4=110

Subtract 4 from both sides of the equation:

10y=106

Divide by the coefficient of y, which is 10:

y=10.6

Substitute 10.6 for y in segments PO & OM:

PO=7(10.6)+12

OM=3(10.6)-8

PO=74.2+12

OM=31.8-8

Solve:

PO=86.2

OM=23.8

Check your answers by substituting:

PO+OM=PM

86.2+23.8=110

8 0
4 years ago
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