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adelina 88 [10]
3 years ago
8

Which programming language represents data in the form of a series of 0s and 1s?

Computers and Technology
1 answer:
Ivan3 years ago
3 0
Binary is represented by 1s and 0s, and is a machine language
You might be interested in
Describe the pace of change in ICT
densk [106]

Answer:

Information and communications technology is an extensional term for information technology that stresses the role of unified communications and the integration of telecommunications and computers, as Technology Trends 2016

#1: Spreading intelligence throughout the cloud. ...

#2: Self-managing devices. ...

#3: Communication beyond sight and sound. ...

#4: Fundamental technologies reshaping what networks can do. ...

#5: Weaving security and privacy into the IoT fabric.

Explanation:

look for a question that i have answered answer it and also plz give me brainliest on this one plz

4 0
3 years ago
A palindrome is a string that reads the same from left to right and from right to left. Design an algorithm to find the minimum
stepladder [879]

Answer:

Explanation:

The following code is written in Python. It is a recursive function that tests the first and last character of the word and keeps checking to see if each change would create the palindrome. Finally, printing out the minimum number needed to create the palindrome.

import sys

def numOfSwitches(word, start, end):

   if (start > end):

       return sys.maxsize

   if (start == end):

       return 0

   if (start == end - 1):

       if (word[start] == word[end]):

           return 0

       else:

           return 1

   if (word[start] == word[end]):

       return numOfSwitches(word, start + 1, end - 1)

   else:

       return (min(numOfSwitches(word, start, end - 1),

                   numOfSwitches(word, start + 1, end)) + 1)

word = input("Enter a Word: ")

start = 0

end = len(word)-1

print("Number of switches required for palindrome: " + str(numOfSwitches(word, start, end)))

3 0
2 years ago
What type of document is a mobile device's EULA?
MakcuM [25]
EULA stands for End User License Agreement. This document is the contract between the software application author or publisher and the user of that application. It is also called "software license", because it establishes the purchaser's right to use the software on the mobile device. T<span>he user agrees to pay for the privilege of using the software, and promises the software author or publisher to comply with all restrictions stated in the EULA. </span>
6 0
3 years ago
Write a Java class to perform the following: 1. Write a method to search the following array using a linear search, ( target ele
Alina [70]

Answer:

Check the explanation

Explanation:

Linear search in JAVA:-

import java.util.Scanner;

class linearsearch

{

  public static void main(String args[])

  {

     int count, number, item, arr[];

     

     Scanner console = new Scanner(System.in);

     System.out.println("Enter numbers:");

     number = console.nextInt();

   

     arr = new int[number];

     System.out.println("Enter " + number + " ");

     

     for (count = 0; count < number; count++)

       arr[count] = console.nextInt();

     System.out.println("Enter search value:");

     item = console.nextInt();

     for (count = 0; count < number; count++)

     {

        if (arr[count] == item)

        {

          System.out.println(item+" present at "+(count+1));

         

          break;

        }

     }

     if (count == number)

       System.out.println(item + " doesn't found in array.");

  }

}

Kindly check the first attached image below for the code output.

Selection Sort in JAVA:-

public class selectionsort {

   public static void selectionsort(int[] array){

       for (int i = 0; i < array.length - 1; i++)

       {

           int ind = i;

           for (int j = i + 1; j < array.length; j++){

               if (array[j] < array[ind]){

                   ind = j;

               }

           }

           int smaller_number = array[ind];  

           array[ind] = array[i];

           array[i] = smaller_number;

       }

   }

     

   public static void main(String a[]){

       int[] arr = {9,94,4,2,43,18,32,12};

       System.out.println("Before Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

       System.out.println();

         

       selectionsort(arr);

       

       System.out.println("After Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

   }

}  

Kindly check the second attached image below for the code output.

Bubble Sort in JAVA:-

public class bubblesort {

   static void bubblesort(int[] array) {

       int num = array.length;

       int temp = 0;

        for(int i=0; i < num; i++){

                for(int j=1; j < (num-i); j++){

                         if(array[j-1] > array[j]){

                           

                                temp = array[j-1];

                                array[j-1] = array[j];

                                array[j] = temp;

                        }

                         

                }

        }

   }

   public static void main(String[] args) {

               int arr1[] ={3333,60,25,32,55,620,85};

               

               System.out.println("Before Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

               System.out.println();

                 

               bubblesort(arr1);

               

               System.out.println("After Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

 

       }

}  

Kindly check the third attached image below for the code output.

Binary search in JAVA:-

public class binarysearch {

  public int binarySearch(int[] array, int x) {

     return binarySearch(array, x, 0, array.length - 1);

  }

  private int binarySearch(int[ ] arr, int x,

        int lw, int hg) {

     if (lw > hg) return -1;

     int middle = (lw + hg)/2;

     if (arr[middle] == x) return middle;

     else if (arr[middle] < x)

        return binarySearch(arr, x, middle+1, hg);

     else

        return binarySearch(arr, x, lw, middle-1);

  }

  public static void main(String[] args) {

     binarysearch obj = new binarysearch();

     int[] ar =

       { 22, 18,12,14,36,59,74,98,41,23,

        34,50,45,49,31,53,74,56,57,80,

        61,68,37,12,58,79,904,56,99};

     for (int i = 0; i < ar.length; i++)

        System.out.print(obj.binarySearch(ar,

           ar[i]) + " ");

     System.out.println();

     System.out.print(obj.binarySearch(ar,19) +" ");

     System.out.print(obj.binarySearch(ar,25)+" ");

     System.out.print(obj.binarySearch(ar,82)+" ");

     System.out.print(obj.binarySearch(ar,19)+" ");

     System.out.println();

  }

}

Kindly check the fourth attached image below for the code output

7 0
2 years ago
This script should:
denis23 [38]

Answer:

the answer is d

Explanation:

5 0
3 years ago
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