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Gelneren [198K]
3 years ago
15

6.8-4.2b=5.6b-3 is this equation identify or has no solution

Mathematics
1 answer:
AfilCa [17]3 years ago
5 0
I would say identity because:
6.8- 4.2b=5.6b-3
6.8=9.8b-3
9.8=9.8b

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A quilt maker is creating a design of a sailboat. she needs exactly the same amount of fabric for the sail as she needs for the
valina [46]
The shape of sail is triangle
The shape of the boat is trapezoid
Fabric needed for sail = fabric needed for boat
which mean ;
                      the area of triangle = the area of trapezoid

the area of triangle = 0.5 * base * height
base = bottom sail = 10 and height = 10
∴  the area of triangle = 0.5 * 10 * 10 = 50 ⇒⇒⇒⇒⇒(1)

the area of trapezoid = 0.5 * (b₁ +b₂) * h
b₁ = long base
b₂ = short base = 10 cm.
h = height = 4 cm.
∴ the area of trapezoid = 0.5 (b₁ + 10 ) * 4 ⇒⇒⇒⇒ (2)

Equating (1) and (2)
∴ 0.5 (b₁ + 10 ) * 4 = 50
    b₁ + 10 = 25
    b₁  = 15

∴ <span>The length of the long base of the trapezoid = 15 cm.

The correct answer is option (C)
</span>





5 0
3 years ago
Read 2 more answers
Which of the following is the complete factorization of 10x - 3 - 3x2? -(3x + 1)(x - 3) -(3x - 1)(x - 3) (3x - 1)(x + 3)
qaws [65]

Answer:

=-\left(3x-1\right)\left(x-3\right)

Step-by-step explanation:

10x-3-3x^2\\\mathrm{Factor\:out\:common\:term\:}-1\\=-\left(3x^2-10x+3\right)\\\mathrm{Factor}\:3x^2-10x+3:\quad \left(3x-1\right)\left(x-3\right)\\3x^2-10x+3\\\mathrm{Write\:in\:the\:standard\:form}\:ax^2+bx+c\\=3x^2-10x+3\\\mathrm{Break\:the\:expression\:into\:groups}\\=\left(3x^2-x\right)+\left(-9x+3\right)\\\mathrm{Factor\:out\:}x\mathrm{\:from\:}3x^2-x\mathrm{:\quad }x\left(3x-1\right)\\3x^2-x\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c\\x^2=xx\\=3xx-x

\mathrm{Factor\:out\:common\:term\:}x\\=x\left(3x-1\right)\\\mathrm{Factor\:out\:}-3\mathrm{\:from\:}-9x+3\mathrm{:\quad }-3\left(3x-1\right)\\-9x+3\\\mathrm{Rewrite\:}9\mathrm{\:as\:}3\cdot \:3\\=-3\cdot \:3x+3\\\mathrm{Factor\:out\:common\:term\:}-3\\=-3\left(3x-1\right)\\=x\left(3x-1\right)-3\left(3x-1\right)\\\mathrm{Factor\:out\:common\:term\:}3x-1\\=\left(3x-1\right)\left(x-3\right)\\=-\left(3x-1\right)\left(x-3\right)

5 0
4 years ago
Read 2 more answers
Please help me with this question.
Sedbober [7]

Answer:

A)c=130/20

B)6.5 calories

Step-by-step explanation:

in one minute the calories burnt are

the equation would be

20 min.=130 calories

1 min.=?c

c=130÷20

part B=130÷20

=6.5 CALORIES

7 0
3 years ago
2X+5+2x+3x= No solution
eimsori [14]

Answer:

12 x is the answer. please thanks and follow me.

8 0
3 years ago
What is the solution of the equation (x – 5)^2 + 3(x – 5) + 9 = 0? Use u substitution and the quadratic formula to solve.
xz_007 [3.2K]

Answer:

x = \dfrac{7 \pm 3i\sqrt{3}}{2}

Step-by-step explanation:

(x – 5)^2 + 3(x – 5) + 9 = 0

This is a quadratic equation in x - 5.

Let u = x - 5, then the quadratic equation becomes:

u^2 + 3u + 9 = 0

We can use the quadratic formula to solve for u.

u = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

u = \dfrac{-3 \pm \sqrt{3^2 - 4(1)(9)}}{2(1)}

u = \dfrac{-3 \pm \sqrt{9 - 36}}{2}

u = \dfrac{-3 \pm \sqrt{-27}}{2}

u = \dfrac{-3 \pm 3i\sqrt{3}}{2}

Since u = x - 5, now we substitute x - 5 for u and solve for x.

x - 5 = \dfrac{-3 \pm 3i\sqrt{3}}{2}

x = \dfrac{-3 \pm 3i\sqrt{3}}{2} + 5

x = \dfrac{-3 \pm 3i\sqrt{3}}{2} + \dfrac{10}{2}

x = \dfrac{7 \pm 3i\sqrt{3}}{2}

7 0
3 years ago
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