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Ghella [55]
4 years ago
14

According to Le Châtelier's principle, how will an increase in pressure affect a gaseous equilibrium system? Shift it toward the

products Shift it toward the reactants Shift it toward the side with higher total mole concentration Shift it toward the side with lower total mole concentration
Chemistry
1 answer:
Ierofanga [76]4 years ago
3 0

Answer:

Shift it toward the side with lower total mole concentration.

Explanation:

  • Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.
  • When there is an increase in pressure, the equilibrium will shift towards the side with fewer moles of gas of the reaction. And when there is a decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
  • <em>So, the right choice is: Shift it toward the side with lower total mole concentration.</em>

<em></em>

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<u>Answer:</u> The metal having molar mass equal to 26.95 g/mol is Aluminium

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  • To calculate the number of moles for given molarity, we use the equation:

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0.5000M=\frac{\text{Moles of }H_2SO_4}{0.1279L}\\\\\text{Moles of }H_2SO_4=(0.5000mol/L\times 0.1279L)=0.06395mol

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  • The chemical equation for the reaction of metal (forming M^{3+} ion) and sulfuric acid follows:

2X+3H_2SO_4\rightarrow X_2(SO_4)_3+3H_2

By Stoichiometry of the reaction:

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