Answer:
0.600 g/cm³
Explanation:
Step 1: Given data
- Height of the cylinder (h): 6.62 cm
- Diameter of the cylinder (d): 2.34 cm
- Mass of the cylinder (m): 17.1 g
Step 2: Calculate the volume of the cylinder
First, we have to determine the radius, which is half of the diameter.
r = d/2 = 2.34 cm/2 = 1.17 cm
Then, we use the formula for the volume of the cylinder.
V= π × r² × h
V= π × (1.17 cm)² × 6.62 cm
V = 28.5 cm³
Step 3: Calculate the density (ρ) of the sample
The density is equal to the mass divided by the volume.
ρ = m/V
ρ = 17.1 g/28.5 cm³
ρ = 0.600 g/cm³
For this problem we use the Avogadro's number which is an empirical value that relates the number of particles to the number of moles. Its approximated value is 6.022×10²³ atoms/mole. The solution is as follows:
4.40×10²⁴ aluminum atoms * 1 moles/6.022×10²³ atoms = 7.306
Thus, there are 7.306 moles of aluminum.
Answer: A. 490.48mol
Explanation:
Using the ideal gas equation; PV =nRT
where P = Presssure = 200 atm
V = Volume = 60L
n = Number of moles
R = Gas constant = 0.08206 L.atm/mol/K
T = Temperature = 25 °C + 273 = 298K
Make "n" the subject of the formular;
n = PV / RT
= 200 x 60 / 0.08206 x 298
= 490.73 mol, which is closest to option A. 490.48mol
Answer:
Reactivity
Explanation:
Examples of chemical properties includes toxicity, acidity, reactivity and heat of combustion
Answer:
A
Explanation:
Because the gravity and the mass of objects are proportionate
