Hello,
f(x)-f(a)= -3x²-5x+1-(-3a²-5a+1)=-3(x²-a²)-5(x-a)=-3(x-a)(x+a)-5(x-a)
=-(x-a)(3(x+a)+5)
=-(x-a)(3x+3a+5)
lim (f(x)-f(a))/(x-a)=- lim (3x+3a+5)=3a+3a+5=-6a-5
if a=1==>-6*1-5=-11
Otherwise
f'(x)=-6x-5
f'(1)=-6-5=-11
at point(1,-7)
Answer: 60
Step-by-step explanation:
From the question, we are informed that pencils come in packages of 10 while erasers come in package of 12 .
We are further told that Phillip wants to purchase the smallest number of pencils and erasers so that he will have exactly 1 eraser per pencil, this simply means that we have to calculate the lowest common multiple for 10 and 12.
Multiples of 10 = 10, 20, 30, 40, 50, 60,
Multiples of 12 = 12, 24, 36, 48, 60, 72
Therefore, the packages of pencils and erasers that Phillip should buy will be 60
Y = mx + b
-3 = -5/2 (2) + b
-3 = -5 + b
b = 2
equation
y = -5/2x + 2
The answer for this problem i −10x2+66xy−36y2−5x+3y
Let's solve it by step by step.
(−5x+3y)(2x−12y+1)
=(−5x+3y)(2x+−12y+1)
=(−5x)(2x)+(−5x)(−12y)+(−5x)(1)+(3y)(2x)+(3y)(−12y)+(3y)(1)
=−10x2+60xy−5x+6xy−36y2+3y
So, -10x2+66xy-36y2-5x+3y
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Answer:
idunnoe
Step-by-step explanation:
sorry