9514 1404 393
Answer:
A. 3×3
B. [0, 1, 5]
C. (rows, columns) = (# equations, # variables) for matrix A; vector x remains unchanged; vector b has a row for each equation.
Step-by-step explanation:
A. The matrix A has a row for each equation and a column for each variable. The entries in each column of a given row are the coefficients of the corresponding variable in the equation the row represents. If the variable is missing, its coefficient is zero.
This system of equations has 3 equations in 3 variables, so matrix A has dimensions ...
A dimensions = (rows, columns) = (# equations, # variables) = (3, 3)
Matrix A is 3×3.
__
B. The second row of A represents the second equation:
The coefficients of the variables are 0, 1, 5. These are the entries in row 2 of matrix A.
__
C. As stated in part A, the size of matrix A will match the number of equations and variables in the system. If the number of variables remains the same, the number of rows of A (and b) will reflect the number of equations. (The number of columns of A (and rows of x) will reflect the number of variables.)
Answer:
y - 10 = -1 (x+4)
y = - x + 6
Step-by-step explanation:
y - 10 = - 1 (x - - 4)
y - 10 = -x - 4
y = -x - 4 + 10
The answer is 16pi
the circumference of a circle is equal to
so the answer is 6 pi
good luck
C would be the answer because to find the area of a circle A=pi times radius squared and you put that in a calculator and get 50.24
Answer:
<h2>y = 9</h2>
Step-by-step explanation:
Put x = 5 to the equation -6x - 3y = -57
(-6)(5) - 3y = -57
-30 - 3y = -57 <em>add 30 to both sides</em>
-3y = -27 <em>divide both sides by (-3)</em>
y = 9