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Mademuasel [1]
3 years ago
11

How do I write the expression using exponents.8⋅w⋅w⋅w⋅w

Mathematics
1 answer:
pentagon [3]3 years ago
4 0

Answer:

8w^4

Step-by-step explanation:

hope this helps!

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<1 is the remote interior angle

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3 years ago
PLEASE HELP!! 100 POINTS!!
Nataliya [291]

Answer:

A. 16 m

B. At t = 2 and t = 6

C. 8 seconds

Step-by-step explanation:

Maximum height is at the vertex

(4,16). So maximum height is 16 m at t = 4

The rocket is at a height of 12m at two distinct times:

At 2 seconds and again at 6 seconds

The rocket is in air when the height is not zero, I.e between t=0 and t=8

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What happens to the function f(x)=x^4 when it becomes f'(x)=x^4+5
il63 [147K]

Answer: It will move up 5 spaces on the y-axis.

Step-by-step explanation: y=mx+b where b is the y-intercept (where it will be on the y-axis). In the 1st one it doesn’t have a b so there is no y-intercept so it will pass through point (0,0). In the 2nd one since your adding 5 it will now pass through point (0,5). Because it shifted up 5 on the y-axis.

3 0
3 years ago
Helium is used for balloons because it is less dense than air. This is what allows helium balloons to rise. Suppose a helium- ai
Kay [80]

Answer: Option A

About 0.02 pounds

Step-by-step explanation:

We know that density is defined as:

d = \frac{m}{v}

Where

d is the density

m is the mass

v is the volume

We want to calculate the helium-air mass of a spherical balloon and we know its density and the diameter of the balloon.

Then we can calculate its mass.

1) We use the diameter of the spherical globe to calculate its volume.

The volume of a sphere is:

V = \frac{4}{3}\pi r ^ 3

and

radius = \frac{diameter}{2}

So

V = \frac{4}{3}\pi(\frac{d}{2}) ^ 3\\\\V = \frac{4}{3}\pi(\frac{1}{2}) ^ 3

V= 0.5236\ ft^3

2) Use the density formula to find the mass

d = \frac{m}{v}

m = vd

m = (0.5236\ ft^3)*(0.04\ \frac{pound}{ft^3})\\\\m = 0.02\ pounds

<em>The answer is 0.02 pounds</em>

5 0
3 years ago
Use the formula for the area of a circle to find the area of the bull’s eye and the next ring together A. 22,686.5 mm2
nirvana33 [79]

Answer:

<h2> B. 31,400 mm2</h2>

Step-by-step explanation:

We know that the bull's eye target has a diameter of 20 centimeters, which equals 200 milimeters.

So, we find the area

A_{target}= \pi (100mm) ^{2} =(3.14)(10000) mm^{2} =31,400 mm^{2}

Therefore, the right answer is B.

7 0
3 years ago
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