Answer: 1000
Step-by-step explanation:
The number of combinations is equal to the product of the number of options for each tumbler.
Each tumbler has 10 possible numbers, and we have 3 tumblers, then the number of combinations is:
C = 10*10*10 = 10^3 = 1000
We have 1000 possible codes for the lock.
Of the 100 students, 37 take only Spanish. Subtracting 37 from 100 gives us 63 students who are taking either both Spanish and Chinese or only Chinese.
So, there are 63 students who are taking Chinese (just Chinese or both Chinese and Spanish).
Since the number of students taking Chinese is 8 more than the number of students taking Spanish, 63 - 8 + 55 students taking Spanish (just Spanish or both Spanish and Chinese).
Of these 55 students, 37 are only taking Spanish, therefore, 55 - 37 = 18 students who are taking both languages.
I guess a whole lot shorter way of looking at this is: for there to be 8 more students taking Chinese than Spanish, there must be 8 more students who are taking only Chinese than who are taking only Spanish: 37 + 8 = 45. Since 37 are taking only Spanish and 45 are taking only Chinese, 100 - (37 + 45) = 18 students who are taking both languages.
Answer:
35 and 70
Step-by-step explanation:
First I would start off by making a list of its multiples.
7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84.
Then find two (or more) of those numbers that can be divided evenly by 5.
35/5 = 7, so 35 works.
70/5 = 14, so 70 works.
Answer:
C should be your answer if I'm not right then forgive me please.
Step-by-step explanation:
Answer:
Trees
Step-by-step explanation: