Question

Can i please have help with number 6

Answer 1

Length of the diameter =   sqrt ( (-12- (-8)^2) +(2-0)^2) )
  = sqrt  (16 + 4) = sqrt20 
so radius = sqrt 20 / 2 = sqrt5
so r^2 = 5


Center of the circle = coordinates of the midpoint of the diameter =

-8-12/2 , 2-0 / 2  =    (-10, 1)

(x - a)^2 + (y - b)^2 = r^2  is general form of a circle so here the circle is:_

(x + 10)^2 + (y - 1)^2 = 5  Answer

Its B