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ExtremeBDS [4]
3 years ago
8

Use the rational zero thereom to list all possible zeroes of the function f(x)= 5x^8-2x^5-7

Mathematics
1 answer:
Scrat [10]3 years ago
4 0

Possible rational zeros are:

\pm1,\pm7,\pm\frac{1}{5},\pm\frac{7}{5}

Step-by-step explanation:

We need to list all possible zeroes of the function f(x)= 5x^8-2x^5-7 using rational zero theorem.

The rational zero theorem.

rational zero theorem states that zeros can be found by dividing the factors of constant term called p by the factors of the leading co-efficient called q i.e

p/q

In our given function  f(x)= 5x^8-2x^5-7

p = 7

q = 5

Factors of p (7) = ±1, ±7

Factors of q (5) = ±1, ±5

\frac{p}{q} =\frac{\pm1,\pm7}{\pm1,\pm5}

So, possible rational zeros are:

\pm1,\pm7,\pm\frac{1}{5},\pm\frac{7}{5}

Keywords: rational zero theorem, possible zeroes

Learn more about rational zero theorem at:

  • brainly.com/question/5030671
  • brainly.com/question/10894205

#learnwithBrainly

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14.  (2x - 1)(x + 7) = 0

Using the zero factor property, we know that either the first or second terms (or both) must be equal to 0 if their product is 0.  We can set each term equal to 0 to find the solutions:

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15.  x^{2} +3x=10

To solve this equation, you first need to set it equal to 0:

x^{2} +3x=10 \\ x^{2} +3x-10 = 0

Next, it can be factored:

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Finally, we can solve just like we did above:

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Now, set the equation equal to 0:

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