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just olya [345]
3 years ago
8

Give the inequality. PLEASE HELP ASAP, THANK YOU

Mathematics
1 answer:
Reil [10]3 years ago
5 0

Answer:

-3\le x\le 1

or

|x+1|\le2


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2(x + 1 ) - 3(x + 5) ≥ 0 please solve!!
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Answer:

Step-by-step explanation:

2x + 2 -3x -15 > 0

-x-13 > 0

-x > 13

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What is the value of v? 4/5(v−7)=2
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I will mark you brainiest if you can answer this
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Triangle ABC has vertices of A(-6, 7), B (4, -1), and C (-2, -9). What is the length of the median from angle B?
jeka94
Coordinates of the midpoint of AC:
M ( (-6-2) / 2) , ( 7-9 ) /2 ) = ( -4, -1 )
d ( BM ) = √ ( 4 + 4 )² + ( -1+ 1 )²
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6 0
3 years ago
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Determine whether the given lengths can be sides of a right triangle. Which of the following are true statements. A.The lengths
Stels [109]

Answer:

Given sides 12, 16 and 20 can be the sides of right triangle.

Step-by-step explanation:

Sides of right triangle always follow the Pythagoras theorem.

i.e (base)^2 + (Height)^2 = (Hypotenuse)^2

For the given Lengths 7, 40 and 41

We need to check if

7^2 + 40^2 =41^2 \\or\\ 7^2 + 40^2 \neq41^2

Since \\7^2 + 40^2 = 1649\\and \\41^2 = 1681

That means, \\ 7^2 + 40^2 \neq 41^2

hence 7,40 and 41 can not be the sides of right triangle.

Next,

Given sides 12,16 and 20.

Again follow the similar process used in the above problem.

12^2 + 16^2 =400\\And \\20^2 = 400\\Since 12^2 + 16^2 = 20^2

Therefore given sides 12,16 and 20 can be the sides of right triangle.


7 0
3 years ago
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