Lets assume the relationship between the amount of blue and red marbles are proportional. If there are 6 red marbles , then we would need need to find out how much times you multiplied 2 by to get.

6/2 is 3, which means that you multiplied the red marbles by 3 to get 6 of them.

Since the relationship between red and blue marbles is equivalent, we just need to multiply the blue marbles by 3 as well, to even it out.

3x3=9

There are 9 blue marbles if there are 6 red marbles.

5 0

2 years ago

For any polyhedron solid the sum of its... and ...is two more than the number of its...

stiks02 [169]

Answer: Sum of vertices and sides is two more than the no. of edges.

Step-by-step explanation:

The basic formula is:

F+V-E=2

F+V=E+2

(NOTE: This applies only for polyhedrons...which means that it doesn't apply for cylinders and spheres and the kind)

6 0

3 years ago

Read 2 more answers

-×^2 - 7x + 7 = -2x^2 to the nearest tenth.

yulyashka [42]

Solving Quadratic Equations

The general form of a quadratic equation is:

$ax^2+bx+c=0$

It can be solved by using the formula:

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

we have the following equation:

$-x^2-7x+7=-2x^2$

we need to put this equation in standard form as explained above

Adding 2x^2:

$\begin{gathered} 2x^2-x^2-7x+7=-2x^2+2x^2 \\ \text{Simplifying:} \\ x^2-7x+7=0 \end{gathered}$

Now we have the equation in the correct form, we find the value of the variables as follows:

a=1, b=-7, c=7

Applying the formula:

$x=\frac{-(-7)\pm\sqrt[]{(-7)^2-4(1)(7)}}{2(1)}$

Operating:

$x=\frac{7\pm\sqrt[]{49-28}}{2}=\frac{7\pm\sqrt[]{21}}{2}$

The square root of 21 is not exact, we use two decimals so far, and we'll round to one decimal at the very last time.

Taking the square root:

$\begin{gathered} x=\frac{7\pm4.58}{2} \\ We\text{ have two solutions:} \\ x=\frac{7+4.58}{2}=7.79 \\ x=\frac{7-4.58}{2}=1.21 \end{gathered}$

The solutions (to the nearest tenth) are:

x= 7.8

x=1.2

Answer complete

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5 0

1 year ago