Question

The length of a rectangular playing field is 5m longer than its width. If the perimeter of the field is 150m,find it's width​

Answer 1

Answer:

35

Step-by-step explanation:

Make equations, l = w+5 and 2l + 2w = 150

Substitute w+5 into 2l + 2w = 150

Simplify to get 4w + 10 = 150

Subtract 10 from both sides to get 4w = 140

Divide both sides by 4 and you get 35 as width

Answer 2

Answer:

The width of the field is 35 meters.

Step-by-step explanation:

Recall that the perimeter of a rectangle is given by:

$\displaystyle P = 2(w+\ell)$

Where w is the width and l is the length of the rectangle.

We know that the perimeter is 150 meters. Thus:

$150=2(w+\ell)$

Divide both sides by two:

$75=w+\ell$

We are given that the length is five meters longer than the width. So:

$\ell = w+5$

Substitute:

$75=w+(w+5)$

Combine like terms:

$75=2w+5$

Subtract five from both sides:

$70=2w$

And divide both sides by two. Hence:

$w=35$

Thus, the width of the rectangular field is 35 meters.