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Vitek1552 [10]
2 years ago
5

Identify the domain of the function shown in the graph.

Mathematics
2 answers:
SVEN [57.7K]2 years ago
7 0

<u>Understanding</u>

The domain of a function is basically all the values where x is defined, and by defined, it means it has a y value corresponding to it. In this graph, x is defined from -5 to 5. If you look outside this range of numbers (from -5 to 5 on the x-axis) you will not find any y values for them. We can easily say the solution is A.

<u>Solution:</u>

[A] -5

<em><u>Note</u></em>: From what I see from the picture -5 and 5 are included in the domain, either the question is incorrectly written, or the picture isn't clear enough. If so, the answer should be -5\leq x\leq 5.

kompoz [17]2 years ago
5 0

<u>Answer:</u>

The answer is A choice.

<u>Explanation:</u>

By looking at the graph, we notice that at the left side, the domain/x-value stops at -5 and 5.

Thus, the domain is at <u>the left end side to the right end side.</u>

The domain stops at -5 on the left side and 5 on the right side. Thus the answer is

-5 < x < 5.

The A choice.

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a) The 99% confidence interval is given by (0.198;0.242).

b) Based on the p value obtained and using the significance level assumed \alpha=0.01 we have p_v>\alpha so we can conclude that we fail to reject the null hypothesis, and we can said that at 1% of significance the proportion of people who are rated with Excellent/Good economy conditions not differs from 0.24. The interval also confirms the conclusion since 0.24 it's inside of the interval calculated.

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<em>Data given and notation   </em>

n=2362 represent the random sample taken

X represent the people who says that  they would watch one of the television shows.

\hat p=\frac{X}{n}=0.22 estimated proportion of people rated as​ Excellent/Good economic conditions.

p_o=0.24 is the value that we want to test

\alpha represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  <em> </em>

<em>Concepts and formulas to use   </em>

We need to conduct a hypothesis in order to test the claim that 24% of people are rated with good economic conditions:  

Null hypothesis:p=0.24  

Alternative hypothesis:p \neq 0.24  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Part a: Test the hypothesis

<em>Check for the assumptions that he sample must satisfy in order to apply the test   </em>

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.  

b) The sample needs to be large enough

np = 2362x0.22=519.64>10 and n(1-p)=2364*(1-0.22)=1843.92>10

Condition satisfied.

<em>Calculate the statistic</em>  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.22 -0.24}{\sqrt{\frac{0.24(1-0.24)}{2362}}}=-2.28

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\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The critical value using \alpha=0.01 and \alpha/2 =0.005 would be z_{\alpha/2}=2.58. Replacing the values given we have:

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Part c

The confidence level assumed was 99%, so then the signficance is given by \alpha=1-confidence=1-0.99=0.01

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