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Vitek1552 [10]
2 years ago
5

Identify the domain of the function shown in the graph.

Mathematics
2 answers:
SVEN [57.7K]2 years ago
7 0

<u>Understanding</u>

The domain of a function is basically all the values where x is defined, and by defined, it means it has a y value corresponding to it. In this graph, x is defined from -5 to 5. If you look outside this range of numbers (from -5 to 5 on the x-axis) you will not find any y values for them. We can easily say the solution is A.

<u>Solution:</u>

[A] -5

<em><u>Note</u></em>: From what I see from the picture -5 and 5 are included in the domain, either the question is incorrectly written, or the picture isn't clear enough. If so, the answer should be -5\leq x\leq 5.

kompoz [17]2 years ago
5 0

<u>Answer:</u>

The answer is A choice.

<u>Explanation:</u>

By looking at the graph, we notice that at the left side, the domain/x-value stops at -5 and 5.

Thus, the domain is at <u>the left end side to the right end side.</u>

The domain stops at -5 on the left side and 5 on the right side. Thus the answer is

-5 < x < 5.

The A choice.

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A soft-drink machine at a steakhouse is regulated so that the amount of drink dispensed is normally distributed with a mean of 2
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Answer:

z=\frac{203-200}{\frac{15}{\sqrt{9}}}=0.6    

p_v =P(z>0.6)=0.274  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can't conclude that the true mean is not significantly higher than 200 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=203 represent the mean height for the sample  

\sigma=15 represent the population standard deviation

n=9 sample size  

\mu_o =200 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 200, the system of hypothesis would be:  

Null hypothesis:\mu \leq 200  

Alternative hypothesis:\mu > 20  

If we analyze the size for the sample is < 30 but we  know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{203-200}{\frac{15}{\sqrt{9}}}=0.6    

P-value

Since is a one sided test the p value would be:  

p_v =P(z>0.6)=0.274  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can't conclude that the true mean is not significantly higher than 200 at 5% of signficance.  

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Volume of square pyramid can be calculated by the formula :

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replace values of each number in equati/on:

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