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Cerrena [4.2K]
2 years ago
8

Eileen drove for 85 minutes. This is 21 more minutes than one third the number of minutes Ethan drove. How do I put this into an

equation?
Mathematics
2 answers:
Lapatulllka [165]2 years ago
6 0
So let's start out by labeling Ethan as X

Since 85 is 1/3 of what Ethan drove, that means Ethan drove 3 times of 85.

85= (3x) -21                                 
85 -21 = 3x
60=3x
20 = x 
xxMikexx [17]2 years ago
5 0

Answer:85= (3x) -21  

Step-by-step explanation:

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(3x-4y)^2-(3x-4y)(3x+4y)
zheka24 [161]

Answer:

-24xy + 32y^2

Step-by-step explanation:

Hello!

We can use the special binomial product formulas:

  • (a + b)^2 = a^2 + 2ab + b^2
  • (a + b)(a - b) = a^2 - b^2

<h3>Simplify</h3>
  • (3x - 4y)^2 - (3x - 4y)(3x + 4y)
  • (9x^2-24xy+16y^2) - (9x^2 - 16y^2)
  • 9x^2 - 9x^2 - 24xy + 16y^2 + 16y^2
  • -24xy + 32y^2

The simplified form is -24xy + 32y^2

6 0
1 year ago
48 = 4t + 12<br> How would I solve this someone please respond fast.
raketka [301]

Answer:

t=9

Step-by-step explanation:

Move all terms that don't contain

t to the right side and solve.t=9

8 0
3 years ago
Read 2 more answers
An online music club sells songs for $.95each plus a $1.95monthly fee for the service. If Maria’s total monthly bill was $14.30,
aksik [14]
First you would subtract the monthly fee from the total bill
14.30 - 1.95 = 12.35
Maria spend $12.35 on songs, to find out how many songs, you divide that by $.95
12.35 \div .95 = 13
Maria bought 13 songs this month.
5 0
3 years ago
what is the probability of flipping a coin 10 times and getting tails8 times? Round your answer to the nearest tenth of a percen
slava [35]
The answer is 8/10 and that simplified is 4/5
4 0
3 years ago
Can anyone explain to me how to do this question ? ty !!​
julia-pushkina [17]

Step-by-step explanation:

use a little imagination.

the whole thing is a combination of churches and half- circles.

and you know the formula for the area of a circle ?

A = pi×r²

so, the only difficulty is to find the circles and then the radius of each involved circle.

when you look at the picture, the shaded area is almost identical to the lower half of the main circle.

2 bumps "look" over into the other side, but one equally sized bump is removed from this lower half.

so, as a first step we will calculate the area of the lower half of the main circle.

the diameter is 24 m, so the radius is half of that : 12m

the area of the large circle is therefore

pi×12² = 144×pi m²

since we only need the (lower) half, we divide this by 2 :

144×pi / 2 = 72×pi m²

the bumps up and down are actually half-circles too. just of smaller circles.

since AB = BC = CD, we know each of these lines are 1/3 of the main diameter AD.

so, the diameter of the smaller circles is 24/3 = 8 m

and their radius is half of that = 8/2 = 4m

the area of such a small circle is therefore

As = pi×4² = 16×pi m²

and a small half-circle area is then

16×pi / 2 = 8×pi m²

so, for the full shaded area I need to take the large half-circle and add 2 small half-circles, and then subtract 1 small half-circle.

so, in total I only need to add 1 small half-circle.

Ashaded = 72×pi + 8×pi = 80×pi m²

5 0
3 years ago
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