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Gemiola [76]
2 years ago
10

A survey was taken of students in math classes to find out how many hours per day students spend on social media. The survey res

ults for the first-, second-, and third-period classes are as follows: First period: 2, 4, 3, 1, 0, 2, 1, 3, 1, 4, 9, 2, 4, 3, 0 Second period: 3, 2, 3, 1, 3, 4, 2, 4, 3, 1, 0, 2, 3, 1, 2 Third period: 4, 5, 3, 4, 2, 3, 4, 1, 8, 2, 3, 1, 0, 2, 1, 3 Which is the best measure of center for third period and why?
Mathematics
2 answers:
Ray Of Light [21]2 years ago
7 0
  Third Period: 4, 5, 3, 4, 2, 3, 4, 1, 8, 2, 3, 1, 0, 2, 1, 3

Measures of central tendency are methods to which an investigator can locate the most central value, or the reoccurring or frequent most value in the set of parameter or statistic. There are three:
Mean. Is the average of the data values
Median. The middlemost value or digit in the data set
Mode. The determining the most frequent parameter To identify which of these three suits the given, arranging them first is a must. Ascending to descending.
Third Period: 0,1,1,1,2,2,2,3,3,3,3 4,4,4,5,8,

The best is mode, why? Because if you observe there is a number most frequent in the data value and it is the fastest way.

Mode = 3



Inga [223]2 years ago
4 0

Answer:

Median, because there is 1 outlier that affects the center

Step-by-step explanation:

Ordering the data from the least value to the highest value we get:

0, 1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 8

Because there are 16 values, positions 8 and 9 are in the half. Both correspond to value 3. Then, the median is 3.

Other measures of center, like the mean, are not the best options because of the presence of the 8 value, which is atypical.

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How to do question 5 and 6. Can you explain the first one which is A for 5 and 6?<br><br>Thank you​
Illusion [34]

for 6

in a

given

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point=(2,-4)=(x1,y1)

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y-y1=m(x-x1)

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4 0
3 years ago
Factor complete −2x2 + 10x.
mezya [45]

The factors of the quadratic equation is (x + 1) and (x - 6)

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The quadratic equation; -2x² + 10x + 12

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Here,

a = -2, b = 10 and c = 12

Now,

\frac{-b(+-)\sqrt{b^{2} -4ac} }{2a} = \frac{-10(+-)\sqrt{10^{2} -4 . -2. 12} }{2.-2} = \frac{-10(+-)\sqrt{100 +96} }{-4} = (-10±14) ÷ -4

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Solve for,

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That is,  (x - 6)

Therefore, the factors for the given quadratic equation is (x + 1) and (x - 6)

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brainly.com/question/9300679

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