When it comes to laplace equations, there are transformation equations to follow. Generally, when you want to transform a laplace equation, you change the equation from f(t) to F(s). If you do the reverse, it is called the reverse laplace equation.
Based on the given, the useful transformation equation is shown in the attached picture.
When the term is s^2, that must mean that the equation is 1!/s^(1+1) to yield 1/s^2. This means that n=1. Taking the reciprocal s^2 must be equal to 1/t. Thus, for the first term, -11s^2 is equal to -11/t. For the second term, n must be equal to 6 so that 6!/s^(6+1) would yield 720/s^7. Thus, 720s^7 is equal to 1/t^6.
Hence, the transformed equation is
-11/t - 1/t^6
Solution for the question asked: 3x^2-5x+4=6
it can be simplified by subtracting 6 from both the sides...
3x^2-5x+4-6=6-6
3x^2-5x-2=0 which is the required form where a=3,b=-5 and c=-2.Now putting the values in the formula we will get two values for x which are 6 and (-1).
hope this will help you
First, add t to each side:
2t - 6 = 8
Add 6 to each side:
2t = 14
Divide both sides by 2:
t = 7
Hope this helps!! :)
Answer:
answer is B
Step-by-step explanation:
as S and T are points on the same line