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Elza [17]
4 years ago
11

The number of kilometers Tony travels in a canoe, d, varies directly with the amount of time spent in the canoe, t. When Tony ca

noes for 2.25 h, he travels 9 km. Which equation shows this direct linear variation?
d = 4t
d = 2t
d = 2.25t
d = 4 + t
Mathematics
1 answer:
HACTEHA [7]4 years ago
7 0

Answer:

d= 4t

Step-by-step explanation:

to find distance, the equation is speed multiplied by time and in this question we are given the time and distance so we have to divide 9km by 2.25hrs to find the speed: 9÷2.25= 4 so, the equation would be d=4t which means that to find distance we need to multiply 4 by the time.

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astra-53 [7]

Answer:

8

Step-by-step explanation:

check this out!

-5(a+3)=- 55

-5a-15=- 55

-5a= -55+15

-5a= -40

-5a/-5 =-40/-5

a=8

4 0
4 years ago
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help? I know what i’m doing somewhat but i really just didn’t wanna pay attention in class the day this was taught
PIT_PIT [208]

To solve the equation for x, first divide both sides of the equation by 4 to get e^{2.7x}=\frac{33}{4}. Then, take the natural logarithm of both sides (base e) to get \ln e^{2.7x} = \ln (33/4). The left hand side of this equation if equal to 2.7x, so we get 2.7x = \ln(33/4). The final step is to divide both sides of the equation by 2.7, to get that x =\frac{ \ln (33/4)}{2.7}. This is approximately equal to 0.782.

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I'm stuck: 20 POINTS AND BRAINLIEST!
Sedbober [7]

Answer:

see explanation

Step-by-step explanation:

The secant- secant angle PRS is half the measure of the difference of the intercepted arcs, that is

\frac{1}{2} (PD - QS) = 50 ( multiply both sides by 2 )

PD - QS = 100, that is

12x + 8 - (4x + 4) = 100

12x + 8 - 4x - 4 = 100

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5 0
4 years ago
A sequence consists of 20102010 terms. Each term after the first is 11 larger than the previous term. The sum of the 20102010 te
Nataliya [291]

You're considering a sequence of in which consecutive terms differ by 1, meaning

<em>a(n)</em> = <em>a</em> (<em>n</em> - 1) + 1

so <em>a(n)</em> is an arithmetic sequence. (I'm guessing 20102010 should actually be 2010, and 53075307 should be 5307, so 11 should probably be just 1.)

The sum of the first 2010 terms is 5307, or

\displaystyle\sum_{n=1}^{2010}a(n)=5307

Find the value of the first term in the sequence, <em>a</em>(1).

We can write <em>a(n)</em> in terms of <em>a</em>(1) by iterative substitution:

<em>a(n)</em> = <em>a</em>(<em>n</em> - 1) + 1

<em>a(n)</em> = (<em>a</em>(<em>n</em> - 2) + 1) + 1 = <em>a</em>(<em>n</em> - 2) + 2

<em>a(n)</em> = (<em>a</em>(<em>n</em> - 3) + 1) + 2 = <em>a</em>(<em>n</em> - 3) + 3

and so on, down to

<em>a(n)</em> = <em>a</em>(1) + <em>n</em> - 1

So the sum of the first 2010 terms is

\displaystyle\sum_{n=1}^{2010}a(n)=\sum_{n=1}^{2010}\left(a(1)+n-1\right)=(a(1)-1)\sum_{n=1}^{2010}1+\sum_{n=1}^{2010}n=5307

Recall that

\displaystyle\sum_{n=1}^N1=\underbrace{1+1+\cdots+1}_{N\text{ times}}=N

and

\displaystyle\sum_{n=1}^Nn=1+2+\cdots+N=\dfrac{N(N+1)}2

So we have

\displaystyle\sum_{n=1}^{2010}a(n)=2010(a(1)-1)+\frac{2010\cdot2011}2=5307

Solve for <em>a</em>(1) :

2010 (<em>a</em>(1) - 1) + 2,021,055 = 5307

2010 (<em>a</em>(1) - 1) = -2,015,748

<em>a</em>(1) - 1 = - 335,958/335

<em>a</em>(1) = - 335,623/335

Now, every second term, starting with <em>a</em>(1), differs by 2, so they form another arithmetic sequence <em>b(n)</em> given by

<em>b(n)</em> = <em>b</em>(<em>n</em> - 1) + 2

or, using the same method as before,

<em>b(n)</em> = <em>b</em>(1) + 2 (<em>n</em> - 1) = <em>a</em>(1) + 2<em>n</em> - 2

The sum of the 1005 terms in this sequence is

\displaystyle\sum_{n=1}^{1005}b(n)=(a(1)-2)\sum_{n=1}^{1005}1+2\sum_{n=1}^{1005}n

= (- 335,623/335 - 2)•1005 + 2•1005•1006/2

= 1146

6 0
3 years ago
I would also love an explanation!
boyakko [2]

Answer:you go up one over three

Step-by-step explanation:

6 0
3 years ago
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