<span>k= Keisha
k + 6=
John</span>
<span>
k + k + 6
= 4k</span>
<span>
2k + 6 ( - 2k)
= 4k ( - 2k)</span>
<span>
6 = 2k</span>
<span>
3 =
k
(Keisha= 3 years old)</span>
<span>
k + 6 = 9
(John = 9 years old)
</span>
3 + 3 + 6 = 4 (3)
<span>
12 = 12
</span><span>So
we made the pawn represent Keisha’s age.
Then we knew that John is 6 years older than Keisha so we represented
his age with a pawn plus 6. This went on 1 side of the equation because it said
that together they equal 4 times Keisha’s age. So on the other side of the
equation we put 4 pawns because we are using each pawn as Keisha’s age. Then we subtracted the pawns from each side
to keep the equation balanced. So we had
that 2 pawns equal 6, which means that each pawn equals 3 so Keisha is 3 years
old. Since John is 6 years older than
Keisha, he must be 9 years old. We
checked our work and substituted 6 in for each pawn and found that 12 equals
12, so our equation is balanced.
</span>
Hope this helps :)
I think it is c im not sure tho choose c or d anyone
Answer:
x^6 + 4,096
Step-by-step explanation:
[(x+4)^2]^3
(x^2 + 16)^3
x^6 + 4,096
Answer:
a. 1/3pi+kpi and 2/3pi+kpi
Step-by-step explanation:
2Sec²x
=2+2tan²x-(tan²x)²=-1
Let tan²x=u
-u²+2u+2=-1
-u²+2u+3=0
u²-2u-3=0
(u+1)(u-3)=0
u=-1,u=3
(tan x)²=-1(No solution)
(tan x)²=3
>>tan x=±sqrt(3)
I) tan x=sqrt(3)
>>tan(pi/3)=sqrt 3
Tan(pi+A) =tanA
Tan(pi+pi/3)=tan(pi/3)
>>tan(4/3pi)=sqrt(3)
>>x=4/3pi and 1/3pi
General solution: 1/3pi+kpi
ii) tan x=-sqrt(3)
x=2/3pi(At 2nd quadrant)
x=5/3pi(at 4th quadrant)
General solution: 2/3pi+kpi
Answer: 196 :)
Step-by-step explanation:
