Find the area of this parallelogram. 8.9 cm 7.1 cm 11.4 cm
2 answers:
<h3>Answer: 80.94 square cm</h3>
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Work Shown:
Area of parallelogram = base*height
Area of parallelogram = 11.4*7.1
Area of parallelogram = 80.94 square cm
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notes:
- The base and height always form a 90 degree angle (as shown by the small square marker).
- The side length of 8.9 cm is never used.
- We can write "square cm" as "cm^2" or
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Answer:68.3 degrees
Step-by-step explanation:
The diagram of the triangle ABC is shown in the attached photo. We would determine the length of side AB. It is equal to a. We would apply the cosine rule which is expressed as follows
c^2 = a^2 + b^2 - 2abCos C
Looking at the triangle,
b = 75 miles
a = 80 miles.
Angle ACB = 180 - 42 = 138 degrees. Therefore
c^2 = 80^2 + 75^2 - 2 × 80 × 75Cos 138
c^2 = 6400 + 5625 - 12000Cos 138
c^2 = 6400 + 5625 - 12000 × -0.7431
c^2 = 12025 + 8917.2
c = √20942.2 = 144.7
To determine A, we will apply sine rule
a/SinA = b/SinB = c/SinC. Therefore,
80/SinA = 144.7/Sin 138
80Sin 138 = 144.7 SinA
SinA = 53.528/144.7 = 0.3699
A = 21.7 degrees
Therefore, theta = 90 - 21.7
= 68.3 degees
