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marishachu [46]
3 years ago
8

Graph the system of equations. {8x+8y=642x−2y=−4

Mathematics
1 answer:
klemol [59]3 years ago
6 0
<span>The graph is attached.

Explanation:
We can use the x- and y-intercepts to graph. The x-intercept of the first equation is 8, and the y-intercept is 8. The x-intercept of the second equation is -2, and the y-intercept is 2.
<span>
x-intercepts are where the data crosses the x-axis. At every one of these points, the y-coordinate will be 0; therefore we can substitute 0 for y and solve to get the value of the x-intercept.

For the first equation, we would have
8x+8(0)=64
8x=64.

Divide both sides by 8:
8x/8 = 64/8
x=8.

For the second equation,
2x-2(0)=-4
2x=-4.

Divide both sides by 2:
2x/2 = -4/2
x=-2.

y-intercepts are where the data crosses the y-axis. At every one of these points, the x-coordinate will be 0; therefore we can substitute 0 for x and solve to get the value of the y-intercept.

For the first equation,
8(0)+8y=64
8y=64.

Divide both sides by 8:
8y/8 = 64/8
y=8.

For the second equation,
2(0)-2y=-4
-2y=-4.

Divide both sides by -2:
-2y/-2 = -4/-2
y=2.

Plot these points for both equations and connect them to draw the line.</span></span>

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Please help with the steps as well!!
mariarad [96]

To solve this problem, we need to use the Pythagorean Theorem, which states that a^2 + b^2 must equal c^2. "a" is the length of one of the legs (shorter sides of the triangle) and "b" is the length of the other leg. "c" is the length of the hypotenuse.

a = y = 36.25cm

b = x = 20.93cm

a^2 + b^2 = c^2

(36.25)^2 + (20.93)^2 = c^2

1314.0625 + 438.0649 = c^2

√1752.1274 = √c^2

c = 41.8584209 ≈ 41.86

So your final answer is...

The length of the hypotenuse is about 41.86 cm.

4 0
3 years ago
out of a senior class of 100 students the.class offers (president vice president treasurer needs to be arranged.com how many dif
kondaur [170]
Answer: 33

explanation: 100/3 = 33.333, and since it isn't possible for 0.333 to be three different students being picked, there are only 33 different ways.
8 0
2 years ago
The equation y=x^3 + 3 is symmetric with respect to which of he following?
lianna [129]

y = x^{3} +3

Subtract 3 from both sides,

y-3=x^{3}

Let x = X and y - 3 = Y

Then,

Y = X^{3}

So, we have shifted the origin to a point (0, 3).

This is an odd function and the graph of an odd function is symmetrical about the origin.

That is, symmetrical about X = 0, Y = 0

Symmetrical about x = 0,, y - 3 = 0

Symmetrical about x = 0, y = 3.

Hence, the graph is symmetrical about the point (0, 3).

3 0
3 years ago
And the black flaure the ima Name a possible rotation and the degree in which it turned
Kruka [31]

Answer is in the file below

tinyurl.com/wpazsebu

3 0
3 years ago
Help, i know the answer but i don’t know how to do the work
Diano4ka-milaya [45]

Answer:

C

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplifying each radical before combining them.

\sqrt{45t}

= \sqrt{9(5t)}

= \sqrt{9} × \sqrt{5t} = 3\sqrt{5t}

-----------------------------------------------------------------------------

\sqrt{125t}

= \sqrt{25(5t)}

= \sqrt{25} × \sqrt{5t} = 5\sqrt{5t}

---------------------------------------------------------------------------

Hence

2(3\sqrt{5t}) - 3(5\sqrt{5t}

= 6\sqrt{5t} - 15\sqrt{5t}

= - 9\sqrt{5t} → C

7 0
4 years ago
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