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3241004551 [841]
3 years ago
13

Will mark as brainiest (Must show work)

Mathematics
1 answer:
kirza4 [7]3 years ago
3 0

Answer:

m∠CAB = 40°

Step-by-step explanation:

DAC = 99

DAB = 59

B is inside DAC, and so is DAB. So CAB must add to 59 to get to 99, nothing over that because it's inside DAC.

So 99 - 59 = 40

CAB must be 40°

That's all I can say for now. Hope this helps and a thank won't hurt! :)

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Candy counted to 600 by 6's, beginning with 6. Danny counted to 600 by 4's beginning with 4. How many the numbers that candy cou
KATRIN_1 [288]

Step-by-step explanation:

If we count for both numbers up to 36, we start seeing a pattern...

Candy: 6 12 18 24 30 36

Danny: 4 8 12 16 20 24 28 32 36

Every other number in Candy's counting is also counted by Danny. So here's what we'll do:

  • Divide 600 by 6

600/6 = 100

This is how many numbers Candy counted overall.

  • Divide the result by 2.

100/2 = 50

This is how many numbers Danny counted that were also numbers Candy counted.

Answer:

50 of the numbers that candy counted were also counted by Danny.

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3 years ago
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Of 60 students, 24 students have a pet. What is the ratio of students with pets to students without pets?
frosja888 [35]

Answer

Find out the what is the ratio of students with pets to students without pets .

To prove

As given

of 60 students, 24 students have a pet.

Thus Total number of student = 60

students have pets = 24

students without  pets = 60 - 24

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Now  ratio of students with pets to students without pets .

\frac{Student\ with\ pets}{Students\ without\ pets} = \frac{24}{36}

simplify the above

\frac{Student\ with\ pets}{Students\ without\ pets} = \frac{2}{3}

Therefore the  ratio of students with pets to students without pets be 2:3 .

Hence proved

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3 years ago
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dolphi86 [110]
Similar figures are figures which has the same shape however they do not always have the same size. It should not be used interchangeably with congruent figures since the latter would refer to figures which has the same size and shape. Thus, congruent figures are always similar figures but similar figures are not always congruent figures. From the choices given, I think the best choice would be the first option. The two squares would be the pair of non-congruent figures that are always similar. This is because no matter what are the side lengths of the squares, it will always have the form of the square.
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Drag the vertices of the triangle below to draw a right triangle with side lengths 10, 24, and 26.
ra1l [238]

Answer:

15 ? :)

Step-by-step explanation:

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3 years ago
The product of 4 and a number x is at least 21
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